作者：木匠小强

带你走进榆林业主的樱桃木美式之家

看看樱桃木都有哪些颜色CP

樱桃木最佳颜色CP

先看玄关客餐厅。进门位置订制格栅经典玄关柜，不多说，直接上图

颜色CP一：樱桃木搭灰调蓝，美式复古

玄关进来，客厅实物图效果图对比看下，电视背景墙颜色都一模一样。樱桃木太适合美式风了，毕竟很多老美都用樱桃木。这种含灰调的复古蓝和樱桃木搭起来很绝，随着樱桃木颜色加深，美式复古感会越来越足 

颜色CP二：樱桃木搭大绿植，绝绝子

客厅随处可见的绿植犹如进入“森林”般的家，很治愈。樱桃木搭绿植没人不爱吧？业主就是被樱桃木+绿植碰撞出的效果吸引，利用出差机会也要来北京看实物，果然是真爱

颜色CP三：樱桃木搭灰白色，万能不出错

温暖樱桃木搭配灰色大理石，让大理石的冰冷感一扫而空。樱桃木家具搭配浅色木地板、木纹砖或灰色系地板，有个明暗对比挺好。很多人觉得家具和地板一定要选类似颜色，这其实也是误区 

业主家有个洗衣房，所以阳台不用晾衣服，放个桌子喝茶看书当然香。万能的白色纱帘搭樱桃木很雅致。当阳光透过白色纱帘，在绿植映称下，空间通透明亮，温馨又典雅

客厅另一侧的餐厅，餐边柜+圆桌，简简单单。圆桌台面采用白色岩板，耐用是一方面，有颜色碰撞才显得更有层次 

通往卧室的走廊，有人挂画，有人放书柜，有人放斗柜，有人放几案，榆林业主选择放一张简美小书桌。别说将书桌当几案用，一点不违和，成为家里另外一景

主卧里的“凯旋门”

主卧最特别的就是这个半包围的「衣帽间」。拍摄帅哥随口说像个「凯旋门」，结果它就有了「凯旋门」衣柜的“尊称”，家人们觉得像不？

这么设计的原因是因为衣柜不放这面墙就只能放床尾。若放这里（主卫门口）传统做法是做L型转角衣柜遮挡主卫门。对这个卧室来说，不想从视觉上挤压横向空间，关键是会挡住原本南北通透的空间。现在这样设计，业主觉得很可

有了「凯旋门」衣柜，卧室一片整洁，一张简美大床，床尾放斗柜+书桌，宽间显得很宽敞，该有的也都有

值得一提的是这张「书桌」，看着是我家标准款简美书桌，其实另有玄机，它还是一个梳妆台，因为台面的一半设计成上翻板，里面还带镜子，办公化妆二合一，妥妥的

两个儿童房

一个清雅一个温馨

业主家订制了两个儿童房，先看男孩房。房间3.93*3米，不到12平。空间不算太大，业主选择这种衣柜+书柜+书桌的一体设计，来解决孩子看书、学习、休息多种需求 

这个书桌和衣柜书柜是一体的，如果你家今后有搬家的可能，书桌也可以做成独立的，这样搬家换地方可以直接搬走 

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女孩房大概10平米左右，长和宽均在3米左右， 订制书桌柜、床、衣柜。业主说女儿睡觉总喜欢贴着墙，怕孩子着凉，所以床在靠墙位置加了围挡，父母的关爱就是这么360不缺席 

简简单单老人房

靠近玄关位置的这间卧室是客卧，偶尔老人来住，业主若有在家办公需求，在这里加个班也不错，所以同样定制一个书桌柜

床+衣柜+斗柜，卧室标配，也没啥好说的，就是这个斗柜为了与衣柜600mm的深度持平，在标准尺寸上进行了加深设计 

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本期案例就到这里

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巩闸净3084如何取消打印机HP color laserjet cp1215双面打印
隆融储15989137866 ______ ＂进入计算机左下角开始菜单,找到1215打印机图标,鼠标右键选择打印首选项,功能菜单,右下方可设置双面打印,自动和手动.尽管我与惠普共事,但是我在此的发言并不代表惠普,只代表我自己.＂

巩闸净3084三棱柱侧楞与底面边长都相等 -
隆融储15989137866 ______ 三分之二倍根号二

巩闸净3084如图,在四棱锥P - ABCD中,四边形ABCD为菱形,∠BCD=60°,△PAB为正三角形,点E,F分别是CD、CP的中点,连接BE、BF、EF.(1)求证:AB⊥PD;(2)... -
隆融储15989137866 ______[答案] (1)证明:∵四边形ABCD为菱形,∴∠BAD=∠BCD=60°,AB=AD,∴△ABD为正三角形. 取AB的中点M,连接PM、DM,则DM... (5分) (2)∵E,F是CD,CP的中点,∴EF∥PD由(1)知AB⊥PD,∴AB⊥EF…..(6分) ∵△BCD为正三角形,∴BE⊥CD, ...

巩闸净3084如图,在棱长为1的正方体ABCD - A1B1C1D1中,P是侧棱CC1上的一点,CP=m.(1)求二面角C1 - DB - C的正切值;(2)试确定m,使得直线AP与平面BDD1B... -
隆融储15989137866 ______[答案] 解法一(几何法): (1)如图,连AC,设AC∩BD=O,连接OC,OC1, 则AC⊥BD,CC1⊥BD, ∴BD⊥平面CC1O, ∴BD⊥CC1, 故∠COC1即为二面角C1-DB-C的平面角 在Rt△COC1中,CC1=1,CO= 2 2 则tan∠COC1= CC1 OC= 2 故二面角C...

巩闸净3084在棱长为1的正方体ABCD - A1B1C1D1中,P是CC1上一点,CP=m -
隆融储15989137866 ______ 要想抑制垂直于AP,则只要垂直于平面AA1C1C即可.所以在垂直于平面AA1C1C的平面BB1D1D里每一条直线都成立.直线A1C1交平面BB1D1D于点q(即A1C1和D1B1中点).所以存在这样一个点.这是思路,过程不好写出来,你自己写吧.

巩闸净3084高一平面向量数量积题 -
隆融储15989137866 ______ p=OP=OC+CP=(a+b)/2+CP 注意CP⊥(a-b) p·(a-b)=[(a+b)/2+CP]·(a-...

巩闸净3084任意四边形ABCD,请在线段BD上找一点P,连接AP,CP,使四边形ABCD的面积恰被折线AP - PC平分,说明理由.过P点引PE//AC,PE交DC于E,连接AE,... -
隆融储15989137866 ______[答案] 纠正你的一处错误,＂PE交BC于E＂而不是＂PE交DC于E＂,下面再解答: 首先,P为BD的中点,即BP=PD 此时S△APB=S△APD,S△CPB=S△CPD ∴S△APB+S△CPB=S△APD+S△CPD ∴四边形ABCD的面积恰被折线AP-PC平分 而S△...

巩闸净3084...平面ABEF⊥平面ABCD,EF∥AB,∠BAF=90°,AD=2,AB=AF=2EF=1,点P在棱DF上.(Ⅰ)求证:AD⊥BF:(Ⅱ)若P是DF的中点,求异面直线BE与CP所成... -
隆融储15989137866 ______[答案] (Ⅰ)证明:因为平面ABEF⊥平面ABCD,平面ABEF∩平面ABCD=AB,AD⊥AB,所以AD⊥平面ABEF,因为BF⊂平面ABEF,所以AD⊥BF;(Ⅱ)因为∠BAF=90°,所以AF⊥AB,因为平面ABEF⊥平面ABCD,且平面ABEF∩平面ABCD=AB,所...

巩闸净3084已知A,B,C三点不共线,对平面ABC外一点O,当向量OP=2向量OA - 向量OB - 向量OC时,点P是否与A,B,C共面 -
隆融储15989137866 ______[答案] 不共面.P,A,B,C共面的充要条件是:对空间任意一点O,有向量OP=m•OA+n•OB+s•OC,其中 m+m+s=1 由于本题中,OP=2OA-OB-OC,2-1-1=0≠1,从而不共面.结论的证明:P,A,B,C共面,则向量CP=m•CA+n•...