作者：绿芯小高

近期随着5600G的降价，这款号称核显能吃鸡的U热度上升，这让我想起了我们这几年装机使用量很高的一块主板华擎A320的。上官网查了下Bios竟然可以支持5代，真的很意外，这个可是2017年上市的，从一代U开始到现在我们已经装出去估计大几百块了，稳定性和反馈都挺好。这次是对之前关于5600G降价幅度的笔记一次评测吧，我不是专业写手啊，大家凑合看。我是专业拿螺丝刀，从业20年我从学徒到现在老师傅，但是有个共同点就是还在带我们老板装机，天天螺丝刀不离手，装了快2万台了，哈哈。 

画个重点A320M的Hdmi口可以上144，这次测试是在2K144的电竞屏上测试的。

不详细，也不专业，全是图，能看懂的自己看，看不懂的留言哈。

先上测试的平台配件

先刷Bios不然不亮，我用的是1600X

系统及驱动版本

温度测试及功耗

跑分图

（鑫硕泰16G 2666的兼容太差，点都点不亮，放弃它了。）

上面3张反映是在bios里改显存完全没用，它是自动调节的，也不知道我改的对不对，求高人指点。

继续对比都是默认显存的。

可以看出跑分和内存大小没关系。

双通道和内存的频率影响很大。

下面上游戏Fps，这些都是在2k 144 环境下测试的。

LoL测试，我同事和我感觉还行，主要我是手残党啊，玩啥都不行。

绝地求生测试，没玩过不知道行不行。

总体来说个人觉得还可以吧，办公打打小游戏还是挺好的，吃鸡还算了。这个u搭配itx的小板子也是不错的选择。

好了，就到这里，都是用手机拍的，不专业，大家凑合看吧。

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篇五：号称核显能吃鸡的5600G搭配通杀1-5代2017年上市的神奇廉价板 A320m到底行不行？

韦溥冰3764如图所示的电路中,R1=20Ω,R2=40Ω,R3=60Ω,R4=40Ω.R5=44Ω.若Uab=140V,C,D端开路,则Ucd=? -
阚玉毕13950537717 ______ 由于CD开路,R2与R5上没有电流,也没有压降,因此CD端电压就是R3两端电压.R3两端电压=140*R3/(R1+R3+R4)=140*0.5=70V.所以CD端电压为70V.

韦溥冰3764求理想运算放大电路U0与Ui的关系 -
阚玉毕13950537717 ______ U0=U01-U02 U01=(1+R2/R1)Ui U02=-R4/R3*U01=-R4/R3(1+R2/R1)Ui U0=(1+R2/R1)Ui+R4/R3(1+R2/R1)Ui=(1+R4/R3)(1+R2/R1)Ui

韦溥冰3764R1=R2=R3=R5=1欧姆,R4=2欧姆,电动势为10伏,求流经各电阻的电流 -
阚玉毕13950537717 ______ 如果是串联:I=U/(R1+R2+R3+R4+R5)=10/6=1.67A 如果一律并联:I1=U/R1=10/1=10A I2=U/R2=10/1=10A I3=U/R3=10/1=10A I4=U/R4=10/2=5A I5=U/R5=10/1=10A

韦溥冰3764华擎a320m - hdv用的是两根万紫千红2400 4g bios显示内存单通道 -
阚玉毕13950537717 ______ 内存一条一条的插,试下,是不是有条内存显示不了.有两个槽的插两条,正常的话是8G内存吧

韦溥冰3764如图所示,AB两点间的总电压为20伏,五个电阻电 阻值均为4欧姆,则安培表的示数为 - -----------;伏特表的 -
阚玉毕13950537717 ______ 解:分析电路(如图) R3与R4串联后与R2并联,电流表测通过R2的电流,电压表测AC两点间的电压.(由于可以认为没有电流通过电阻R5,) 设BD之间电压为U2,则根据串联电路分压特点 (U-U2)/U2=R1/(R3+R4)R2/(R3+R4+R2)...

韦溥冰3764如图所示,R1=12kΩ,R2=8kΩ,R3=20kΩ,R4=6kΩ,当电位器滑动触头C凋到最上端和最下端时,AB间的总电 -
阚玉毕13950537717 ______ 电位器滑动触头C调到最上端时,并联部分的电阻为: R并==kΩ=8.4kΩ 此时总电阻为:R=R并+R4=8.4+6=14.4kΩ 电位器滑动触头C调到最下端时,并联部分的电阻为: R并===6.4kΩ 此时总电阻为:R=R并+R4=6.4+6=12.4kΩ 电位器滑动触头C调到中间某个位置时使并联的两个支路的电阻相等时,AB间电阻最大,并联部分最大电阻为: R并=?=*40kΩ=10kΩ 最大总电阻为:R=R并+R4=10+6=16kΩ 答:当电位器滑动触头C凋到最上端和最下端时,AB间的总电阻分别是14.4kΩ和12.4kΩ,AB间最大电阻值为16kΩ.

韦溥冰3764已知E1=20V,E2=4V,R1=10欧,R2=2欧,R4=3欧,电压表的读数为16V,求R3的阻值 -
阚玉毕13950537717 ______ 因为电压表读数为16V,所以I=(E-U)/R1=0.4A; 由闭合电路欧姆定律得:E1-E2=I(R1+R2+R3+R4),所以R3=[E1-E2-I(R1+R2+R4)]/I=25欧姆.

韦溥冰3764如题图,已至R1等于30欧姆,R2等于20欧姆,R3等于60欧姆,R4等于10欧姆,求等效电阻ab -
阚玉毕13950537717 ______ R1R2R3都是一端与a相连,一端与R4相连,所以R1R2R3并联,再串联R4. 等效电阻:R=1/(1/R1+1/R2+1/R3)+R4 =1/(1/30Ω+1/20Ω+1/60Ω)+10Ω =10Ω+10Ω =20Ω

韦溥冰3764为什么惠斯通电桥原理中四个电阻两两的比值相等? -
阚玉毕13950537717 ______ 因为在两个电阻的串联电路中,电阻的分压分别是: U1=R1/(R1+R2)*U U2=R2/(R1+R2)*U 另一支路两电阻的分压是: U3=R3/(R3+R4)*U U4=R4/(R3+R4)*U 所以: 电桥平衡时:R1/R2=R3/R4

韦溥冰3764在图3 - 26中,电流表读数为0.2A,电源电动势E1=12V,外电路电阻R1=R3=10欧姆,R2=R4=5欧姆,则E2=? -
阚玉毕13950537717 ______ R总=R1+R2+R3+R4=30欧 U总=IR总=0.2*30=6v E2=E1-U总=12-6=6v