confess+my+love
甫琳追3854已知两条直线l1:mx+8y+n=0和直线l2:2x+my - 1=0;求满足下列条件时相应m,n的值:(1)l1与l2相交于点A(m, - 1);(2)当m>0,l1∥l2,且l1在x轴上的截距为1;(3)l... -
成修阁18317369840 ______[答案] 两条直线l1:mx+8y+n=0和直线l2:2x+my-1=0. (1)将点P(m,-1)代入两直线方程得:m2-8+n=0 和 2m-m-1=0, 解得 m=1,n=7. (2)由 l1∥l2得:m2-8*2=0,m=±4, 又两直线不能重合, ∴有 8*(-1)-mn≠0,对应得 n≠2m, 又l1在x轴上的截距为1, ∴当m=4,n=-...
甫琳追3854已知直线l1:2x+my+3=0与直线l2:3x - y - 1=0相互垂直,则实数m等于______. -
成修阁18317369840 ______[答案] ∵直线l1:2x+my+3=0与直线l2:3x-y-1=0相互垂直,∴ −2 m•3=-1,∴m=6, 故答案为6.
甫琳追3854《baby one more time》的中文歌词 -
成修阁18317369840 ______ How was I supposed 2 know ? 我怎么会知道? That something wasn't right here. 有些事情不对劲. Oh,baby baby ! 噢,宝贝,宝贝 ! Oh,baby baby ! 噢,宝贝,宝贝 ! I shouldn't have let U go. 我本不该让你走. And now U're out of sight ...
甫琳追3854已知两条直线l1:mx+8y+n=0和l2:2x+my - 1=0;试确定m,n的值,分别使(1)l1与l2相交于点P(m, - 1);(2)l1⊥l2且l1在y轴上的截距为 - 1. -
成修阁18317369840 ______[答案] (1)∵l1与l2相交于点P(m,-1), ∴ m2−8+n=02m−m−1=0, 解得 m=1n=7; (2)由垂直关系可得2m+8m=0, 解得m=0, 又l1在y轴上的截距为-1, ∴− n 8=-1, 解得n=8
甫琳追3854已知直线l1:(m+2)x - (m - 2)y+2=0,直线l2:3x+my - 1=0,且l1⊥l2,则m等于( ) -
成修阁18317369840 ______[选项] A. -1 B. 6或-1 C. -6 D. -6或1
甫琳追3854...lie next to her,And confess your love,your love,As well as your folly,And can you kneel before the king,And say I'm clean,I'm clean,So tell me now where was my... -
成修阁18317369840 ______[答案] Can you lie next to her,你能否躺在她身边, Give her your heart,your heart,奉献给她你的心,你的心. As well as your body,连同你的身体 And can you lie next to her,你能否躺在她身边, And confess your love,your love,倾诉你的爱意,你的爱意 ...
甫琳追3854三元一次方程组无解条件 ax+by+cz=k dx+ey+fz=p lx+my+nz=q a b c d e f l m n k p q 的关系不要用行列式 通俗点的 -
成修阁18317369840 ______[答案] 化ax+by+cz-k=0、 dx+ey+fy-p=0 lx+my+nz-q=0方程组无解就是3个函数图像没有交点,在座标系中平行.剩下的你应该会了
甫琳追3854【高中一年级数学】已知直线L的方程为x - my+2+3m=0 若L与线段y= - 2x - 4 [ - 3≤x≤1] 有共点,求m得范围 -
成修阁18317369840 ______[答案] x-my+2+3m=0.(1) y=-2x-4.(2) (2)代入(1):x-m(-2x-4)+2+3m=0 (2m+1)x+7m+2=0 x=-(7m+2)/(2m+1) ∵-3=
甫琳追3854已知抛物线C:y^2=2px(p>0)过点A(1,2),不过点A的直线l:x=my+n交抛物线C于P,Q两点,且向量AP*向量AQ=0.(Ⅰ)求证:n=2m+5;(Ⅱ)是否存在直线l,使得(... -
成修阁18317369840 ______[答案] (1)将 A 坐标代入抛物线方程可得 p=1 ,因此抛物线方程为 y^2=4x . 与方程 x=my+n 联立可得 y^2-4my-4n=0 , 设P(x1,y1),Q(x2,y2), 则 y1+y2=4m ,y1*y2= -4n , 所以 x1+x2=m(y1+y2)+2n=4m^2+2n , x1*x2=(my1+n)*(my2+n)=m^2*y1y2+mn(y1+y2)+n^...