cos的三次方怎么化简

钮试面3882(π/2)cos3(π/2) 请问如何化简?求详解 -
贾萱趴13556846153 ______[答案] (π/2)[cos(π/2)[^3 =(π/2)*0^3 =0 (π/2)cos[3(π/2)] =(π/2)*0 =0

钮试面3882cos((arccosx)/3)怎么化简 -
贾萱趴13556846153 ______ cos和arccos约分,化为x/3

钮试面3882化简:tan(派减a)cos三次方(负a减派)分之sin平方(a加派)cos(派加a)cot(负a减派) 急 -
贾萱趴13556846153 ______ sin²(α+π)cos(π+a)cot(-α-π)/[tan(π-α)cos³(-α-π)]= sin²αcosacotα/(-tanαcos³α)= sinαcos²a/(-sinαcos²α)= -1.

钮试面3882化简cos平方A+cos平方(派/3 - A)+cos平方(派/3+A) -
贾萱趴13556846153 ______ cos²A+cos²(π/3-A)+cos²(π/3+A)= cos²A+(1+cos(2π/3-2A))/2+(1+cos(2π/3+2A))/2= cos²A+(2+2cos2π/3*cos2A)/2= cos²A+(2-cos2A)/2= cos²A+3/2-(cos2A+1)/2=cos²A- cos²A+3/2=3/2

钮试面3882关于三角比诱导公式,1化简(1 - cotα的四次方)*sinα的平方+ cotα的平方2.已知0<θ<π,且sinθ-cosθ=1/2,则 sinθ的三次方 — cosθ的三次方=? -
贾萱趴13556846153 ______[答案] 1、 原式=(1-cos^4a/sin^4a)*sin²a+cos²a/sin²a =sin²a-cos^4a/sin²a+cos²a/sin²a =sin²a+(cos²a-cos^4a)/sin²a =sin²a-cos²a(1-cos²a)/sin²a =sin²a-cos²asin²a/sin²a =sin²a-cos²a =-cos2a 2、 sinθ-cosθ=1/2 平方 sin²θ-2...

钮试面3882化简:{cot(θ+4π)·cos(θ+π)·sin2次方(θ+3π)}/{tan(π+θ)·cos3次方( - π - 化简:{cot(θ+4π)·cos(θ+π)·sin2次方(θ+3π)}/{tan(π+θ)·cos3次方( - π - θ)} -
贾萱趴13556846153 ______[答案] 我讲希特用a代替 化简=cota*(-cosa)*sin^2a/tana*(-cos^3)=1

钮试面3882cos(3π - α)怎么化简 -
贾萱趴13556846153 ______[答案] cos(2π+π-α)=cons(π-α)=-cosα 三角函数的基本公式还要加强记忆,

钮试面3882cos(3π - x)化简 -
贾萱趴13556846153 ______ 解:cos(3π-x)=cos[2π+(π-x)]=cos(π-x)=cosπcosx+sinπsinx=-1*cosx+0*sinx=-cosx

钮试面3882高一数学题,怎么化简
贾萱趴13556846153 ______ 解:sin(2π-θ)=sin(-θ)= - sinθsin(π/2+θ)=cosθcos(π+θ)= - cosθcos(-θ)=cosθ故f(π/3)=[2cos³(π/3)+sin²(π/3)+cos(π/3)-3] / [2+2cos²(π/3)+cos(π/3) ]= - 1/2(希望能帮到你,满意请及时采纳) 你按我说的算一下

钮试面3882化简:(1)、tan(2π+α)tan(π+α)cos( - π - α)的3次方分之sin( - α)的平方乘以cos(π+α); -
贾萱趴13556846153 ______ ⑴、原式=[(-sina)^2*(-cosa)]/[tana*tana*(-cosa)^3]=sin^2a/(tan^2a*cos^2a)=sin^2a/sin^2a=1;⑵、原式=[(-sina)*tana]/(-cosa)*[(-tana)]=-sina/cosa=-tana.