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cosxy求导

来源:baiyundou.net   日期:2024-09-28

樊刘常1271cosxy+x06*y求导 -
葛瑾祝13180029615 ______ cosxy+x^2 *y 那么对x求偏导数的话 得到 -sinxy *y+2xy 同理y的偏导数为 -sinxy *x +x^2

樊刘常1271求导:已知y=cos(xy),求y的一阶导数(用隐函数求导) -
葛瑾祝13180029615 ______ 解:对等式两边求导,得 y'=-sin(xy)*(y+xy') y'=-ysin(xy)/[xsin(xy)+1]

樊刘常1271cos(x²)求导
葛瑾祝13180029615 ______ 复合函数求导cosx^2=(-sinx^2)*2x

樊刘常1271求导:已知y=cos(xy),求y的一阶导数 -
葛瑾祝13180029615 ______ 对两边分别求导,得 dy/dx=-sin(xy)*(x*dy/dx+y) 则dy/dx(1+sin(xy)*x)=-sin(xy)*y 所以dy/dx=(-sin(xy)*y)/(1+sin(xy)*x)

樊刘常1271利用对数求导法求函数的导数 y=(cos)^x -
葛瑾祝13180029615 ______ y = [cosx]^x lny = x * lncosx y'/y = lncosx + x * 1/cosx * -sinx y'/y = lncosx - xtanx y' = y(lncosx - xtanx) y' = (lncosx - xtanx)[cosx]^x

樊刘常1271解微分方程y'+cosxy=e^( - sinx) -
葛瑾祝13180029615 ______ y'+cosx y=e^(-sinx) 两边同乘以 e^(sinx),得 e^(sinx)y'+cosxe^(sinx)y=e^(-sinx)·e^(sinx)=1 左边=(ye^(sinx))' 即 (ye^(sinx))'=1 所以 通解为: ye^(sinx)=x+c 即 y=xe^(-sinx)+ce^(-sinx)

樊刘常1271x cosy=y,隐函数求导 -
葛瑾祝13180029615 ______ 对x求导 cosy-xsiny*y'=y' 得出y'=cosy/(1+xsiny)

樊刘常1271sinxy=1,那么相等于多少? -
葛瑾祝13180029615 ______ xy=2kπ+π/2 ,k=Z

樊刘常1271函数y=(cosx)^x求导 -
葛瑾祝13180029615 ______ y=(cosx)^x lny=xlncosx 1/y*y ' =lncosx+x/cosx*(-sinx)=lncosx-xtanx ∴y'=(lncosx-xtanx)*y=(lncosx-xtanx)(cosx)^x 上面那位朋友求错啦

樊刘常1271y=(cosx)三次方,,求Y的N次求导...追50分,如题...3/4 COS(X+N PI/2)+(3/4)^N COS (3X+N PI/2) -
葛瑾祝13180029615 ______[答案] cos3x = 4(cosx)^3 - 3cosxy = (cosx)^3 = 1/4 * (cos3x) + 3/4 * cosx(cosx)' = -sinx = cos(x+Pi/2)(cosx)'' = - cosx = cos(x+2*Pi/2)(cosx)n次导 = cos(x + n * Pi/2)y(n次导) = 3/4 * cos(x + n*Pi/2) + 1/4 * ...

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