count+sb+in

厍万唯2389Count me on 和count me in 都可以表示算上我吗? -
祖泊盆13697446042 ______ count me in 是＂算上我＂. Count on me 不是.count on 依靠,指望 I'll count on it.我就指望它了.Great, I'll count on it!好极了,我就指望它了!That was the only thing they could count on.那是他们唯一依靠的东西.You can count on me.你可以指...

厍万唯2389JAVA 编程,输入一串字符,找出出现最多的字符 -
祖泊盆13697446042 ______ import java.util.Scanner; public class Maintest { public static void main(String[] args) { System.out.println(＂输入字符串＂); Scanner sc=new Scanner(System.in); String str=sc.next(); char[] cs=str.toCharArray(); int[] c=new int[256]; int i=0; while(i...

厍万唯2389throw+sb+in+at+the+deep+end是什么意思 -
祖泊盆13697446042 ______ at the deep end 是一个短语,从难入手,指在没有任何准备的情况下接受一个比较难的任务.英文解释: given a difficult job to do without preparation.例句: I was thrown in at the deep end when my company sent me to run the German office. I was only given two day's notice to prepare.

厍万唯2389C语言高手帮帮忙! -
祖泊盆13697446042 ______ #include <stdio.h> #define MAX 50 struct few { float a; float b; float c; }; struct student { int num; char name[30]; float ave; struct few score; }; void display(int,char *,float); void main() { struct student stu[MAX]; struct student temp; struct student in; int i=0,...

厍万唯2389You can count on it!什么意思 -
祖泊盆13697446042 ______ 你尽管相信好了,尽管放心.

厍万唯2389对任意正整数n,设计一个程序求s=1+1/2+1/3+……+1/n的值.写出程序框图和程序语句,要详细内容
祖泊盆13697446042 ______ 程序比较简单,具体如下: #include <stdio.h> int main() { float s = 0.0; int n = 100; for(int count=1;count<=n;count++) { s = s + 1.0/count; } printf(＂%02.f\n＂, s); return 0; }

厍万唯2389count (数) the+ 什么 -
祖泊盆13697446042 ______ count the trees count the pencils count the books

厍万唯2389count the blessings -
祖泊盆13697446042 ______ count the blessings 数算XX给你的恩典 In a blue funk 惊恐万状,忧心忡忡

厍万唯2389为啥超时呢 求指教 杭电1005, #include<stdio.h> int count(int n,int a,int b) {if(n==1... -
祖泊盆13697446042 ______ #include<stdio.h> int count(int n,int a,int b) { if(n==1||n==2) return 1; else return a*count(n-1,a,b)+b*count(n-2,a,b); } main() { int n,a,b,s; scanf(＂%d %d %d＂,&a,&b,&n); while((a+b+n)!=0) { s=count(n,a,b)%7; printf(＂%d\n＂,s); scanf(＂%d %d %d＂,...