health2+fun

莫泊瑞2092c语言:用递归法输出下列数列{an}的前n项,其中:a0=1,a1=2,an+2=an+1+an+1 -
迟昨严18812708054 ______ #include<stdio.h> fun(int n) { if(n==0) return 1; if(n==1) return 2; return fun(n-2)+fun(n-1)+1; } main() { int i,n; printf(＂请输入n:＂); scanf(＂%d＂,&n); // 你这里多了一个分号 for(i=0;i<n;i++) { printf(＂a%d=%d\n＂,i,fun(i)); } }

莫泊瑞2092谁有health2二维码截屏 -
迟昨严18812708054 ______ 抱歉,我无法提供任何未经授权的截图或二维码.请注意,这些内容可能会违反法律法规或道德规范,并且可能会对其他用户造成伤害或不便.请保持言辞文明,遵守社交网络的使用规则.

莫泊瑞2092初二英语作文keep healthy -
迟昨严18812708054 ______ Keep Healthy As the development of the society, health is becoming more and more important in our daily life. As the saying goes, you're what you eat. So to eat the right thing in the right way is the key to keep healthy. Most fruit and vegetables are ...

莫泊瑞2092编写函数fun其功能是,根据整型形参m,计算如下公式,y=1/2!+1/4!+1/m!... -
迟昨严18812708054 ______ float fun(float m) { float sum=1,i,y=0; for(i=2;i<=m;i++) sum*=i; //这里是求m! while(m!=0) { y+=1/sum; sum=sum/(m)/(m-1); m-=2; } return y; } 讲解一下,求m!那里应该能看得懂吧,我就不多说了.... 从while循环那里开始,我是进行...

莫泊瑞2092in a hurry是什么意思 -
迟昨严18812708054 ______ in a hurry意思:迅速地,匆忙地;急切,赶紧;立刻,轻易地 相似短语: 1、in such a hurry 如此匆忙 2、hurry on 赶快去 3、hurry back 迅速回来 hurry 读法 英 [ˈhʌri] 美 [ˈhɜːri] 示例: Kate was in a hurry to grow up, eager for knowledge and...

莫泊瑞2092英语翻译题,快点 -
迟昨严18812708054 ______ 1. Reading in the sun is harmful to our eyes, but Walking after supper and doing eye exercises is good for our health. 2. We have/had fun climbing. 3. her 30-year-old brother 4. Children are yelling at the strange animal with sharp teeth. 5. We should be friendly to each other.

莫泊瑞2092八年级上册英语词组 -
迟昨严18812708054 ______ Unit 1 1. go to the movies = go to the cinema = see a film/movie 看电影 2. look after = take care of 照顾 3. surf the Internet 上网 4. healthy lifestyle 健康的生活方式 5. go...

莫泊瑞2092fun的功能:求整数X的Y次方的低3位值. -
迟昨严18812708054 ______ long fun(int x,int y,long *p ) { int i; long t=1;found*for(i=1; i<=y; i++) //<=yt=t*x; *p=t;...

莫泊瑞2092编写函数fun其功能是:根据整型形参m,计算如下公式的值:y=1/2!+1/4!+... -
迟昨严18812708054 ______ 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 floatfun(intm) { floaty; inti,j,s; if(m%2 != 0 || m<2) //不是偶数 { printf(＂Input Error!\n＂); return-1; } for(y=0,i=2;i<=m;i+=2) { s=1; for(j=1;j<=i;j++) //求n! { s*=j; } y+=1.0/s; } returny; }