render+sb+sth

应该怡2732It's+adj.+of sb+to do sth是什么意思 -
奚果肺14734362048 ______ 你好, It's+adj.+of sb+to do sth 是一种固定句型 表示:某人做某事怎么样 例如: It's kind of you to help me . 你能帮助我真是太好了. It's silly of him not to forgive others for their mistakes. 他不肯原谅别人的过错真是太傻了.

应该怡2732It's+形容词+for sb+动词不定式,是什么语法结构??? -
奚果肺14734362048 ______ it是形容词主语,动词不定式是真正的主语,故也可写成:动词不定式 +BE +形容词+for sb . 如It 's important for us to learn English well .= To learn English well is very important for us .

应该怡2732设r、s、t是三次方程8X³+1001X+2008=0的三个根,则(r+s)³+(s+t)³+(t+r)³的值为 - -- -
奚果肺14734362048 ______ r、s、t是三次方程8X³+1001X+2008=0的三个根 方程可以写成 8(x-r)(x-s)(x-t)=0 展开 即 8x³-8(r+s+t)x²+8(rs+rt+st)x-8rst=0 对比 8X³+1001X+2008=0 得 r+s+t=0 8(rs+rt+st)=1001 -8rst=2008 得 rst=-251 根据公式 a³+b³+c³-3abc=(a+b+c)(a²...

应该怡2732sb+be+adj+to do是不是适用于任何形容词的 -
奚果肺14734362048 ______ 这个句式只适合于一部分形容词. She is kind to help me.这种说法是不对的,应该说It is kind of her to help me. 请记得采纳!

应该怡2732it's+abj+of sb+to do sth -
奚果肺14734362048 ______ adj是说明sb的品质特点用of sb; 说明to do sth用for sb (说人的用of sb. 说事的用for sb.) It's very nice of you to help me. 你来帮助我,你真是太好了.It's very hard for him to study two languages. 对他来说学两门外语是很难的.用介词后面的代词作主语,用介词前边的形容词作表语,造个句子.如果道理上通顺用of,不通则用for.如: You are nice. (通顺,所以应用of). He is hard. (人是困难的,不通,因此应用for.)

应该怡2732设A是m*n矩阵,若存在非零的n*s矩阵B,使得AB=O,证明秩r(A)<n -
奚果肺14734362048 ______ 因为A是m*n矩阵,则r(A)

应该怡2732用一下句式翻译 It is +名词+for sb+to do ath 我受邀到这儿来做关于如何组用一下句式翻译It is +名词+for sb+to do ath我受邀到这儿来做关于如何组织全球环境... -
奚果肺14734362048 ______[答案] 我受邀到这儿来做关于如何阻止全球环境恶化的演讲非常荣幸 It is a pleasure for me to be invited here to make the speech on how to prevent the global environment from deteriorating .

应该怡2732设绝对值小于1的全体实数的集合为s,在s中定义一种运算*,使得a*b=(a+b)/(1+ab),证:如果a,b属于s,那么a*b也属于s. -
奚果肺14734362048 ______[答案] 因为a、b绝对值小于1,故ab

应该怡2732lt is+adj+for sb+to do sth造句 -
奚果肺14734362048 ______[答案] lt is+adj+for sb+to do sth 对某人做…… It is easy for him to finish his jobs. 完成工作对他来说很容易.

应该怡2732三个超难几何问题之三,敬请专家们给予解答.已知锐角三角形ABC的垂心H,外接圆和内切圆半径分别为R和r.求证:AH+BH+CH=2(R+r).[注:通过测量,结... -
奚果肺14734362048 ______[答案] 根据四点共圆有CH*hc=(a*cosC)*b, 又hc*c/2=S(S为三角形面积) 可得CH=(abc/(2S))*cosC=(abc/(2S))*(a^2+b^2-c^2)/(2ab)=(c*a^2+c*b^2-c^3)/(4S) 类似可求得AH,BH AH+BH+CH=(c(a^2+b^2-c^2)+b(a^2+c^2-b^2)+a(b^2+c^2-a^2))/(4S) 由r(a+b+c)/2=...