sin+2xdx

詹诸军4161∫sin xdx=(); -
强凯武17785571788 ______[答案] 因为(cosx)'=-sinx 所以,∫sinxdx=-∫(cosx)'dx=-cosx+C

詹诸军4161定积分∫1在上 - 1在下x^2sinxdx -
强凯武17785571788 ______[答案] 用分部积分 ∫x^2sinxdx =-∫x^2d(cosx) =-x^2cosx+∫cosxd(x^2) =-x^2cosx+2∫xd(sinx) =-x^2cosx+2xsinx-2∫sinxdx =-x^2cosx+2xsinx-2cosx 代入得 ∫1在上-1在下x^2sinxdx=0

詹诸军4161不定积分∫sin2xdx过程 -
强凯武17785571788 ______ ∫sin2xdx=(1/2)∫sin2xd(2x)=-(1/2)cos2x + C

詹诸军4161∫sin的二次方x乘以cos四次方的xdx怎么求,求过程,感谢. ∫sin^2xcos^4xdx=? -
强凯武17785571788 ______ 解:∫sin²xcos^4xdx=∫sin²xcos²xcos²xdx=∫(1/4)sin²2xcos²xdx=(1/4)∫(1/4)(1-cos4x)*(cos2x+1)dx=(1/16)∫(cos2x+1-cos4xcos2x-cos4x)dx=(1/16)[∫cos2xdx+∫dx-∫cos4xcos2xdx-∫cos4xdx]=(1/16)[(1/2)sin2x+x-(1/2)∫cos4xd(sin2x)-(1/4)sin4x]=(...

詹诸军4161求不定积分x方sinxdx 设y=1 - x/1+x,求y' -
强凯武17785571788 ______[答案] ∫x²sinxdx=-∫x²dcosx=-x²cosx+2∫xcosxdx=-x²cosx+2∫xdsinx=-x²cosx+2(xsinx-∫sinxdx)=-x²cosx+2xsinx+cosx+c由y=1-x/(1+x)得y=1/(1+x)y'=-1/(1+x)²

詹诸军4161∫[0,π/2] x^2sinxdx -
强凯武17785571788 ______[答案] ∫[0,π/2] x²sinxdx =-∫[0,π/2] x² dcosx =-x²cosx [0,π/2] +∫[0,π/2] cosx d(x²) =2∫[0,π/2] xcosx dx =2∫[0,π/2] x dsinx =2xsinx[0,π/2] - 2∫[0,π/2] sinx dx =π+2cosx[0,π/2] =π-2

詹诸军4161定积分(1, - 1) x2Sinxdx -
强凯武17785571788 ______[答案] 定积分(1,-1) x2Sinxdx 希望过程步奏详细点 方法1.∫ x^2sinxdx=∫-x^2dcosx=-x^2cosx+∫cosxdx^2=-x^2cosx+∫2xcosxdx=-x^2cosx+∫2xdsinx=-x^2cosx+2xsinx-∫2sinxdx=-x^2cosx+2xsinx+2cosx将(1,-1)代入 得∫ ...

詹诸军4161d( )=2xdx,d( )=sinxdx,xdx=( )d(1 - x^2),(1/x^2)dx=( )d(1/x) 4个空 知道的说下谢谢. -
强凯武17785571788 ______[答案] d(x²)=2xdx,d(-cosx)=sinxdx,xdx=(-1/2)d(1-x^2),(1/x^2)dx=(-)d(1/x)

詹诸军4161∫1/sinxdx求积分,1比sinx -
强凯武17785571788 ______[答案] ∫1/sinxdx=ln|tanx/2|+C=ln|cscx-cotx|+C ∫1/sinxdx=∫sinxdx/sin²x=ʃdcosx/(cos²x-1)=ʃdt/(t²-1)=ln|(t-1)/(t+1)|+C=1/2 ln|(cosx-1)/cosx+1)...

詹诸军41612sin xdx= -
强凯武17785571788 ______[答案] ∫ 2sinxdx=-2cosx +C