(x-1)(x+1)

温张娅579x+1与x - 1是互为相反数吗? -
丘忽迫13098749330 ______[答案] 你要了解相反数的定义,a,b互为相反数,当且仅当a+b=0. 那么,若x+1与x-1互为相反数,当且仅当(x+1)+(x-1)=0,即x=0. 所以,只有当x=0时,他们才互为相反数. 其次,若1/(x+1)和1/(x-1)互为相反数,当且仅当1/(x+1) + 1/(x-1) = 0,即x=0. 所...

温张娅579计算下列各题; (x - 1)(x+1)=__ - (x - 1)(x²+x+1)=__ - (x - 1)(x³+x²+x+1)=___1)猜想(x - 1)(x^n+x^n - 1+x^n - 2+…+x+1)的结果是___2)证明你的猜想 -
丘忽迫13098749330 ______[答案] (x-1)(x+1)=x²-1, (x-1)(x²+x+1)=x³-1, (x-1)(x³+x²+x+1)=x^4-1 1),(x-1)(x^n+x^n-1+x^n-2+…+x+1)的结果是x^(n+1)-1 2),证明:(x-1)(x^n+x^n-1+x^n-2+…+x+1)=x(x^n+x^n-1+x^n-2+...

温张娅579求y=x - 1分之x+1的导数 -
丘忽迫13098749330 ______[答案] y=(x-1)/(x+1)=(x-1+2)/(x-1)=1 +2/(x-1) y'=[1+2/(x-1)]' =1'+[2/(x-1)]' =0+[(-1)*2/(x-1)²](x-1)' =2/(x-1)² 或者直接利用公式(u/v)'=(u'v-uv')/v²来 y'=[(x+1)'(x-1)-(x-1)'(x+1)]/(x-1)² =[(x-1)-(x+1)]/(x-1)² =2/(x-1)²

温张娅579设x - 1/x+1=t,如何用t表示x要一步一步的过程~ -
丘忽迫13098749330 ______[答案] x-1/x+1=t x-i=t(x+1) x-1=tx+t x-tx=1+t x=1+t/1-t

温张娅579(x+1)(x - 1)=x+1(用分解因式法) -
丘忽迫13098749330 ______[答案] (x+1)(x-1)=x+1 移项得: (x+1)(x-1)-(x+1)=0 提取公因式(x+1)得: (x+1)[(x-1)-1]=0 x+1=0 x-2=0 x=-1 或者 x=2

温张娅579(x+1)(x - 1)去括号 -
丘忽迫13098749330 ______[答案] (x+1)(x-1) =x(x-1)+1*(x-1) =x²-x+x-1 =x²-1

温张娅579计算: (1)(x - 1)(x+1)=x² - 1, (x - 1)(x²+x+1)=x³ - 1 -
丘忽迫13098749330 ______[答案] (x-1)(x+1) =x(x+1)-(x+1) =x²+x-x-1 =x²-1 (x-1)(x²+x+1) =x(x²+x+1)-(x²+x+1) =x³+x²+x-x²-x-1 =x³-1 明白请采纳, 有新问题请求助,

温张娅579观察下列等式:(x - 1)(x+1)=x - 1, -
丘忽迫13098749330 ______ 2^9+2^8+2^7+……+2+1=(2-1)*(2^9+2^8+2^7+……+2+1)=2^10-1=1023 ^表示乘方.

温张娅579(x+1)(x - 1)(x2 - x+1)(x2+x+1)等于多少啊 -
丘忽迫13098749330 ______ (x+1)(x-1)(x2-x+1)(x2+x+1)=[(x+1)(x^2-x+1)][(x-1)(x^2+x+1)]=(x^3+1)(x^3-1)=x^6-1

温张娅579(x+1)(x - 1)怎么算都忘了,请指点
丘忽迫13098749330 ______ (x+1)(x-1)=x的平方-1 运用平方差公式的逆运算 平方差公式:a方-b方=(a+b)(a-b)