∑x+2怎么算
央视网消息：2023年招生，有什么亮点？都有哪些培养方式？为夯实人才培养基础，许多高校依托自身优势特点，积极打造特色多元的人才培养体系，为考生提供多样化的成才路径。
南京理工大学钱学森学院是该校拔尖创新人才的培养高地，学院涵盖机械工程类、电子信息类、材料化工类3个专业方向。2023年，将通过高考直招录取模式，在全国招收100人，采取“本硕博”贯通培养的模式。在钱学森班基础上，2022年，学校又探索成立了鼎新创新人才班，2023年计划招收30人。
在复旦大学，“2+X”本科培养体系已基本完善。
据介绍，“2+X”本科培养体系采用学分制，多元发展路径学分约占25%，在弹性学制下，学生可以自由修读各类课程，获取各类学习资源。
在南开大学，学校构建了“8+4+X”拔尖特色人才培养体系。学校的8个伯苓班、4个定制双学位班、15个新工科新文科人才培养平台，面向新生提供近1000个名额。学生入学时可按照个人兴趣和能力，通过选拔进入特定培养项目，选拔比例占新生总人数的25%。
（央视网）
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甫古飘2550∑为x/2+y/3+z/4=1在第一卦限部分,求∫∫(z+2x+4y/3)ds -
诸戴显18382112701 ______ ∑:0原式=∫dx∫(4-2x-4y/3+2x+4y/3)dy=∫4(3-3x/2)dx=(12x-3x^)|=12.
甫古飘2550统计学问题,回归方程的,根据某地区历年人均收入(元)与商品销售额(万元)资料计算的有关数据如下:(x代表人均收入,y代表销售额)n=9 ∑x=546 ... -
诸戴显18382112701 ______[答案] 1)y=bx+a 用公式 b为: (∑xy-nx'y' )/[∑x^2-n(x')^2] , x', y'分别为xi, yi的平均值 求出了b之后,再用公式算出a=y'-bx' n=9 x'= ∑x/9=546/9=182/3, y'= ∑y/9=260/9 b=(16918-9*182/3*260/9)/[34362-9*(182/3)^2]=(3434/3)/1238=0.9246 a=260/9-182/3*0...
甫古飘2550计算∫∫yzdzdx+2dxdy,其中∑是上半球面z=√(4 - x^2 - y^2)的上侧 -
诸戴显18382112701 ______[答案] 添加∑1:z=0下侧,由高斯公式: ∫∫∑+∑1=∫∫∫zdxdydz ∫∫∑=-∫∫(∑1)2dxdy+∫∫∫zdxdydz =8π+(1/2)∫∫(4-x^2-y^2)dxdy =8π+(1/2)∫(0,2π)dθ∫(0,2)r(4-r^2)dr =8π+π∫(0,2)(4r-r^3)dr =12π
甫古飘2550求幂级数∑x^(2n)/(2n)!的和函数 -
诸戴显18382112701 ______[答案] consider Taylor expansion of e^x e^x = 1 + x + x^2/2!+ ...+ x^n/n!+.(1) e^(-x) = 1-x+x^2/2!+..;...+ (2) (1)+(2) e^(x) +e^(-x) = 2(1+x^2/2!+x^4/4!+...) = 2∑x^(2n)/(2n)! ∑x^(2n)/(2n)!=(1/2)(e^(x) +e^(-x))
甫古飘2550如何求求和函数(n+1)(n+2)x^n的和 -
诸戴显18382112701 ______[答案] 积分得: ∑(0,+∞)(n+2)x^(n+1) 再积分得: ∑(0,+∞)x^(n+2)=x^2/(1-x) |x|
甫古飘25504x+2 - 2x=9怎么算 -
诸戴显18382112701 ______ 4x+2-2x=9 解:2x+2=92x=9-22x=7 x=3.5
甫古飘2550求一般项为n^2·x^n的级数的和函数 -
诸戴显18382112701 ______[答案] ∑n^2·x^n=x+2^2 x^2+3^2x^3+.=x(1+2^2 x+3^2x^2+.)=xf(x) 对f(x)积分得:x+2x^2+3x^3+...=x(1+2x+3x^2+...)=xg(x) 对g(x)积分得:x+x^2+x^3+...=x/(1-x) |x|
甫古飘2550求x的n+1次方/(n+1)(n+2) 的和函数? -
诸戴显18382112701 ______[答案] 令原式=f(x)=∑x^(n+1)/(n+1)(n+2) 则g(x)=xf(x)=∑x^(n+2)/(n+1)(n+2) 求导:g'(x)=∑x^(n+1)/(n+1) 再求导:g＂(x)=∑x^n=1/(1-x), 收敛域|x|积分:g'(x)=-ln(1-x)+C1 因g'(0)=0,所以有C1=0 g'(x)=-ln(1-x) 再积分:g(x)=-xln(1-x)+x+ln(1-x)+C 由g(0)=0,得:...
甫古飘2550求幂级数的和函数时常用到几何级数的和函数,那么∑x^(2n - 1)/2^n=(x/2)/(1 - x^2/2)是怎么来的? -
诸戴显18382112701 ______[答案] ∑(1/x)*[(x^2/2)^n] 等比级数求和,公比为(x^2/2),首项为(x^2/2) 所以 =(1/x)*(x^2/2)/[1-(x^2/2)] =(x/2)/(1-x^2/2)
甫古飘2550X=30 ∑X2=190 ∑5 怎么计算均数和标准差 -
诸戴显18382112701 ______[答案] ∑X=30 ∑x^2=190 n=5 //: 题似有误,i 改了一下,. E(X)=∑X/n=30/5=6 //: 计算均值:五个数相加为30,均值为:6; D(X)=∑X^2/5-6^2=190/5-36=2 //: 计算方差:方差等...