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五年级多边形面积30道

来源:baiyundou.net   日期:2024-08-22

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甘裴南1797一五年级算多边形面积题,急急急急急急急急急!!!!
羿澜呼13667015555 ______ 解:设原来正方形的边长是x平方厘米,原来正方形的面积是x²平方厘米 (x+3)²=x²+39 (x+3)X(x+3)=x²+39 x(x+3)+3(x+3)=x²+39 x²+3x+3x+3X3=x²+39 x²+6x+9=x²+39 6x=x²-x²+39-9 6x=30 x=5 ∴x²=25 答:原来正方形的面积是25平方厘米

甘裴南1797两道五年级上册《多边形的面积》数学题 -
羿澜呼13667015555 ______ S=AH.由题意可知3A=18 A=6 6H=24 H=4 S=6X4=24 S=150X50÷2=3750 1762.5÷3750=0.47

甘裴南1797五年级 多边形的面积 练习十七 第三题
羿澜呼13667015555 ______ 第一个:18-12=6 18*9=162 9*6÷2=27

甘裴南1797一道五年级上学期第5章《多边形的面积》题
羿澜呼13667015555 ______ 画个图 增加的面积是两个长方形和一个小正方形,这个小正方形的边长是5厘米 两个长方形的宽是也是5厘米,长是原正方形的长 小正方形的面积是5*5=25平方厘米 则一个长方形的面积是(95-25)÷2=35平方厘米 则长方形的长是35÷5=7厘米也就是原正方形的边长 原正方形的面积是7*7=49平方厘米

甘裴南1797五年级图形面积计算题 -
羿澜呼13667015555 ______ 郭敦顒回答: 此钝角三角形面积=25m*12m=300m².

甘裴南1797小学五年级上册多边形的面积习题.务必写出计算过程. -
羿澜呼13667015555 ______ 假设最上层为1层,根据题意,1层5跟钢管,2层6根(每相邻两层之间差一根),3层7根,依次类推,层号和钢管都是差4,则15根那层的层号应比钢管数小4,即第11层,(感觉是最笨的方法了) 等差数列貌似小学还没学,那就这样共11层,...

甘裴南1797五年级数学面积题
羿澜呼13667015555 ______ 设上一个三角形的高为x 则S△CBE=38-S△ADE=38-1/2(DE*x)=38-1/2(7x)=38-7x/2 则△CBE的高为:(38-7x/2)/(1/2*CE)=(38-7x/2)/(1/2(5+7))=(38-7x/2)/6=(76-7x)/12 列方程得;1/2(EG*x+EF*(76-7x)/12)=65 化简:((13+6)*x+7(76-7x)/12)=130 19x+(532-49x)/12=130 228x+532-49x=1560 179x=1028 x=5.743 所以S△ADG=1/2(DG*x)=1/2(7+13+6)*5.743=74.659

甘裴南1797五年级上学期多边形的面积易错题三角形的易错题,平行四边形的易错题,梯形的易错题,以及组合图形的易错题.不一定非是易错的,只要是能引起同学争议... -
羿澜呼13667015555 ______[答案] 平行四边形 1 、长方形的周长 =( 长 + 宽 ) * 2 【长 = 周长÷ 2- 宽;宽 = 周长÷ 2- 长】 字母公式: C 长方形周长 =(a+b) * 2 长方形的面积 = 长*宽 字母公式: S 长方形面积 =ab 2 、正方形的周长 = 边长* 4 字母公式: C 正方形的周长 =4a 正方形...

甘裴南1797Y5《数学报》——多边形的面积 整理和复习(一)上的“智慧小博士”实验小学五年级同学在进行广播操表演时,围成了一个直角三角形,已知每条边上的... -
羿澜呼13667015555 ______[答案] (16x2)x(21x2)

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