物理作为一门理科科目，一直都是学生们学习的难点。今天给大家分享一些关于高中物理实验的动图，希望有助于大家的理解。

直线运动

打点计时器测速度

用DIS测定瞬时速度

自由落体

追及问题—匀加速追匀速

追及问题—匀减速追匀速

真空玻璃管物体的运动

力和力的平衡

不规则物体的重心

演示玻璃瓶的微小形变

演示桌面的微小形变

探究胡克定律

探究力的平行四边形法则

用DIS研究力的分解

牛顿运动定律

力的作用是相互的

用DIS研究牛顿第三定律

验证牛顿第二定律

弹簧测力计演示超重与失重

传送带模型相对位移

动能定理

探究功与速度的关系

动量问题

人船模型

探究碰撞中的不变量

恒定电流

研究路端电压

探究欧姆定律

探究电阻的伏安特性曲线

探究小灯泡伏安特性曲线

用DIS研究小灯泡U-I图像

用DIS测电源电动势和内阻

多用电表测电池内阻

伏安法测电阻分压接法

灵敏电流计改装成电流表

灵敏电流计改装成电压表

半偏法测量电流表内阻

半偏法测量电压表内阻

静电场

感应起电的本质

验证库仑定律

静电屏蔽

等量同种点电荷的电场线

等量异种点电荷的电场线

测量等势线

探究电容大小的影响因素

磁场

分子电流假说

回旋加速器的原理

地磁场

条形磁体的磁场

蹄形磁体的磁场

带电粒子在磁场中的运动

带电粒子在电磁场中的运动

机械波

波发生明显衍射的条件

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习怖茜2912(2014?徐州三模)某电视娱乐节目装置可简化为如图所示模型.倾角θ=37°的斜面底端与水平传送带平滑接触 -
蒯万凯17569516818 ______ (1)A到B过程:根据牛顿第二定律 mgsinθ-μ1mgcosθ=ma1 , 代入数据解得a1=2m/s2,t1=3s. 所以滑到B点的速度:vB=a1t1=2*3m/s=6m/s, 物块在传送带上匀速运动到C,t2= l v0 = 6 6 s=1s 所以物块由A到B的时间:t=t1+t2=3s+1s=4s (2)斜面上...

习怖茜2912如图所示为货场使用的传送带的模型,传送带倾斜放置,与水平面夹角为θ=37°,传送带AB长度足够长,传送 -
蒯万凯17569516818 ______ (1)设货物刚滑上传送带时加速度为,货物受力如图所示:根据牛顿第二定律得 沿传送带方向:mgsinθ+F f =ma 1 垂直传送带方向:mgcosθ=F N 又F f =μF N 由以上三式得:a 1 =g(sinθ+μcosθ)=10m/s 2 方向沿传送带向下. (2)货物速度从v 0 减...

习怖茜2912如图所示为车站使用的水平传送带的模型,传送带长L=8m,以速度v=4m/s沿顺时针方向匀速转动,现有一个质量 -
蒯万凯17569516818 ______ 设旅行包在传送带上做匀减速运动的时间为t1,即经过t1时间,旅行包的速度达到v=4m/s, 由牛顿第二定律,有旅行包在滑动摩擦力作用下做匀减速直线运动所以有: μmg=ma 代入数据可得:a=6m/s2 取初速度方向为正方向,则滑动摩擦力方...