奇瑞瑞虎8鲲鹏版七座
智电出行获得了疑似奇瑞瑞虎8 PRO新能源的价格和部分配置信息：新车价格区间为15.99万元-17.99万元，7座版本在此基础上增加3,000元，由于产能有限，纯享版为广告版型，暂不供货。瑞虎8 PRO新能源搭载360°全景影像、电动尾门、多色氛围灯、女王副驾等配置。
瑞虎8 PRO新能源座舱搭载24.6英寸一体式双联屏，内置L2级智驾辅助系统。入门版提供LED大灯、静音玻璃、SONY 8扬声器音响、全景天窗等配置；悠享版在入门版基础上增加了18英寸轮毂、行车记录仪、手机无线充电等；纵享版提供前排座椅加热、第2排睡眠头枕、选装HUD+氛围灯等。
瑞虎8 PRO新能源搭载1.5T发动机+双电机的动力组合，0-100km/h加速7.2s。新车针对瑞虎8 PLUS鲲鹏e+上出现的换挡顿挫问题进行优化，匹配3挡DHT混动专用变速箱，WLTC亏电油耗降至5.9L/100km，综合续航提升至1000km+。
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秋面高2476如图,在平面直角坐标系中,△A1A2A3,△A3A4A5,△A5A6A7,△A7A8A9,…,都是等边三角形,且点A1,A3,A5,A7,A9的坐标分别为A1(3,0),A3(1,0),A5(4,0),... -
汲悦届15762757249 ______[答案] 观察,发现规律:A2(2, 3),A4( 5 2,- 33 2),A6(2,2 3),A8( 5 2,- 53 2),…, ∴A4n+2(2, 3n+ 3),A4n+4( 5 2,- (2n+3)3 2)(n为自然数), ∵100=4*24+4, ∴A100的坐标为( 5 2,- 513 2). 故答案为:( 5 2,- 513 2解析看不懂?免费查看同类题视频解析查看解答
秋面高2476因式分解若a2+a= - 1,则a4+2a3 - 3a2 - 4a+3的值为 a的平方加a= - 1 则a的四次方加上2乘以a的3次方减去3乘以a的二次方 - 4乘以a加3 的值为多少 次方打不出来... -
汲悦届15762757249 ______[答案] a^n是a 的n次方的意思 a^4+2a^3-3a^2+3 =a^4+a^3+a^3+(a^2-a^2)-3a^2+3 =a^2*(a^2+a)+a*(a^2+a)-4a^2-4a+3 =(a^2+a)*(a^2+a)-4*(a^2+a)+3 =(a^2+a)^2-4*(a^2+a)+3 这时候如果直接将a^2+a=-1带入,则有: 原式=(-1)^2-4*(-1)+3 =1+4+3 =8 ...
秋面高2476在等差数列{an}中,a1=1,a5=9.(1)求a3;(2)记bn=2an,证明:数列{bn}是等比数列;(3)对于(2)中的Sn,求函数f(n)=Sn - t•2n(n∈N*,t为常数且t∈[0,8])的... -
汲悦届15762757249 ______[答案] (1)a3= a1+a5 2=5---------(2分) (2)由a1=1,a5=9得,an=2n-1 当n≥2时, bn bn−1=4, 所以数列{bn}是以2为首项,4为公比的等比数列-------(5分) (3)由(2)可得,Sn= 2(1−4n) 1−4= 2 3(4n−1)------(7分) 所以,f(n)= 2 3(4n−1)−t•2n= 2 3(...
秋面高2476等差数列的公差和等比数列公比笔怎么求等差数列a1a2a3,2a1=a1+a3 例如:a1=1 a2=2 a3=3 那么2a2=a1+a3→4=1+3可是我想知道他们的公差怎么求,虽... -
汲悦届15762757249 ______[答案] 通过列方程求解. 1、如:等差数列中,有a2²=a1a3,则(a1+d)²=a1(a1+d),化简,得:a1d+d²=0,再结合公差d是否为0进行计算;【等差中的等比项】 2、如:等比数列中,有a2、a4、a5成等差数列,则2a4=a2+a5,即:2a1*q³=a1*q...
秋面高2476(2014•贵阳模拟)已知等差数列{an}中,a3=9,a8=29.(Ⅰ)求数列{an}的通项公式及前n项和Sn的表达式;(Ⅱ)记数列{1anan+1}的前n项和为Tn,求T100的值. -
汲悦届15762757249 ______[答案] (Ⅰ)∵等差数列{an}中,a3=9,a8=29, ∴ a1+2d=9a1+7d=29, 解得a1=1,d=4, ∴an=1+(n-1)*4=4n-3. Sn=n+ n(n−1) 2*4=2n2-n. (Ⅱ)由(Ⅰ)得 1 anan+1= 1 (4n−3)(4n+1)= 1 4( 1 4n−3− 1 4n+1), ∴Tn= 1 4(1- 1 5+ 1 5− 1 9+…+ 1 4n−3− 1 4n+1) = 1 ...
秋面高2476等差数列的公差和等比数列公比笔怎么求 等差数列a1a2a3,2a1=a1+a3 例如:a1=1 a2=2 a3=3 那么2a2=a1+a3→4=1+3可是我想知道他们的公差怎么求,虽... -
汲悦届15762757249 ______[答案] 通过列方程求解. 1、如:等差数列中,有a2²=a1a3,则(a1+d)²=a1(a1+d),化简,得:a1d+d²=0,再结合公差d是否为0进行计算;【等差中的等比项】 2、如:等比数列中,有a2、a4、a5成等差数列,则2a4=a2+a5,即:2a1*q³=a1*q...
秋面高2476(2013•荆门)下列运算正确的是( ) -
汲悦届15762757249 ______[选项] A. a8÷a2=a4 B. a5-(-a)2=-a3 C. a3•(-a)2=a5 D. 5a+3b=8ab
秋面高2476设等比数列{an}的前n项和为Sn,若a1= - 2,S4=4S2,则a3的值为______. -
汲悦届15762757249 ______[答案] ∵等比数列{an}的前n项和为Sn, a1=-2,S4=4S2, ∴a1+a2+a3+a4=4(a1+a2) ∴a3+a4=3(a1+a2), ∴q2=3, ∴a3=a1q2=-2*3=-6, 故答案为:-6
秋面高2476已知等差数列{an}的各项均为正数,a1=3,前n项和为Sn,{bn}是等比数列,公比q=2,且a2b2=20,a3b3=56(1)求an与bn (2)求数列{anbn}的前n项和Tn 过程希... -
汲悦届15762757249 ______[答案] (1) an=a1+(n-1)d=3+(n-1)d bn=b1*q^(n-1)=b1*2^(n-1) a2b2=(3+d)*2b1=20 a3b3=(3+2d)*4b1=56 d=2 b1=2 an=2n+1 bn=2^n (2) anbn=(2n+1)*2^n Tn=3*2+5*2^2+7*2^3+...+(2n+1)*2^n 2Tn=3*2^2+5*2^3+...+(2n-1)*2^n+(2n+1)*2^(n+1) Tn-2Tn=3*2+2(2...
秋面高2476纸张规格大小,(如A3 A4 A5 B3B4B5 18K 32K 64K 48K等)谁知道它们顺序大小(不必分A B K只按大小排序), -
汲悦届15762757249 ______[答案] 开本按照尺寸的大小,通常分三种类型:大型开本、中型开本和小型开本.以787*1092的纸来说,12开以上为大型开本,16~36开为中型开本,40开以下为小型开本,但以文字为主的书籍一般为中型开本.开本形状除6开、12开、20开、24开、40开近...