输出斐波那契数列的前30项
荀薛世3870VC编程,显示Fibonacci数列的前30项(每行5输出项). -
郑轮常15054409303 ______ #include ＂stdafx.h＂#include #include using namespace std; void main() { int a=1,b=1,c,i=28; cout< while(i--) { c=a+b; cout< if(i%5==0) cout< b=a; a=c; } }//斐波那契数列有好多算法,如果单是显示,简单地用几个变量就行了
荀薛世3870设计C程序,完成功能:输出Fibonacci数列的前30项.要求按每行5个数的格式输出该数 -
郑轮常15054409303 ______ #include <stdio.h> int fib(int n) { if (n==1 || n==2) return 1; return fib(n-1)+fib(n-2); } int main() { int i; for (i=1; i<=30; i++){ if (i%5) printf( ＂%d ＂,fib(i) ); else printf( ＂%d\n＂,fib(i) ); } return 0; }
荀薛世3870斐波那契数列 前30项的和 与第30项到底是多少啊,找了一天答案了!有人吗 -
郑轮常15054409303 ______[答案] 前 30 项的和为 2178308 ,第 30 项为 832040 .
荀薛世3870(Java)打印斐波那契数列的前30项,并统计前30项的和. -
郑轮常15054409303 ______ public class Test { public static void main(String[] args) { int sum = 0; for (int i = 1; i int fib = fibonacci(i); sum += fib; System.out.println(＂第＂ + i + ＂项:＂ + fib); } System.out.println(＂和:＂ + sum); } /** 递归版fibonacci函数 * @param n ...
荀薛世3870编写程序输出fibonacci数列的前30项,要求每行输出6项 -
郑轮常15054409303 ______ #include <stdio.h> int a[30]; int main() { a[0] = a[1] = 1; for(int i=2;i<30;i++) a[i] = a[i-1] + a[i-2]; for(int i=0;i<30;i++) { printf(＂%3d ＂, a[i]); if((i+1)%6 == 0) printf(＂\n＂); } printf(＂\n＂); return 0; }
荀薛世3870如何用vb编程求打印fibonacci 数列的前30项 -
郑轮常15054409303 ______ Private Sub Command1_Click() Dim a(30) As Long a(1) = 1: a(2) = 1 For i = 3 To 30 a(i) = a(i - 1) + a(i - 2) Next i n = Len(Str(a(30))) + 2 b = 1 For i = 1 To 30 c = Len(Str(a(i))) + 1 Print Tab(b * n - c); a(i); b = b + 1 If i Mod 5 = 0 Then Print b = 1 End If Next i End Sub
荀薛世3870vb代码利用函数过程和递归两种算法实现斐波那契数列前30项的显示(求大神指点,急用,写的具体些) -
郑轮常15054409303 ______ 窗体中放入Text控件和命令按钮.取text中的数字作为N代码如下Private Function F(n As Long) As Long If n > 2 Then F = F(n - 1) + F(n - 2) Else F = 1 End If End FunctionPrivate Sub Command1_Click() Cls Dim I As Long I = Val(Text1.Text) Print ＂第＂ I ＂项:＂ F(i) End Sub
荀薛世3870java编程实现输出fibonacci数列(要求利用数组实现)的前30项 -
郑轮常15054409303 ______ public class MathTest{ public static void main(String[] args) { int arr[] = new int[30]; arr[0] = arr[1] = 1; for (int i = 2; i < arr.length; i++) { arr[i] = arr[i - 1] + arr[i - 2]; } for (int i = 0; i < arr.length; i++) { if (i % 5 == 0) System.out.println(); System.out.println(arr[i]); } } }
荀薛世3870VFP编程:斐波拉契数列,第一项为0,第二项为1,求前30项的和! -
郑轮常15054409303 ______[答案] clear a=1 b=1 s=0 for i=1 to 18 c=a+b s=s+c a=b b=c endfor ＂斐波拉契数列前30项的和:＂,s
荀薛世3870VF求Fibonacci数列的前30项(急用) -
郑轮常15054409303 ______ set talk off clear DECLARE f(30) f(1)=1 f(2)=1 for i= 3 to 30 f(i)=f(i-1)+f(i-2) next for i=1 to 30? ＂第＂,i,＂项为:＂,f(i) next set talk on