作者：西瓜小智

之前佳能R7用了段时间

由于4K60帧没有超采

画质不是很满意

所以又买了FX30

FX30之前价格都比较高

最近算是有所下降

买的没手柄全新

包装内就说明

电池 充电器 数据线和FX30机身

它虽然是电影机

不过机身和无反差不多

用起来不会不习惯

外型和FX3一模一样

就是传感器变小了

整体做工非常不错

背面按键丰富 

可设置的自定义按键很多

拍照方面没啥好说

传感器支持2600W像素

可以拍，缺少连拍

应该很少人会用它拍照吧

视频主要是可以拍4K120

不过它的4K120是众多机型里

画质比较差的

而4K60帧画质就非常好

首先视频模式 F档 给我整懵了

不过后来查了下

快门光圈ISO对应三个按键

的手动和自动

我还是换成原本的A档M档

比较习惯

菜单基本和A7S3一样 早已习惯

SD卡我是买了张600多元的V90

没有买索尼的CFA卡

想到以后可能还会换相机

还是SD卡比较通用

FX30拍最高规格的4K120

 V90的卡是够用的

画质方面4K120画质会差一点 

而且有很大裁切

镜头换算就当M43直接乘以2就好了

50的镜头就变成100了

而且就算白天  4K120

也有很多的噪点

用达芬奇降噪下

才会有比较好的效果

而4K60帧锐度不错

听说是和富士XT3用同一快底

画质完全可用

可见索尼刀法精准

不想给太多

不然可能会影响A7S3的销量

现在4K120最好用的还是A7S3

要画质有画质，要对焦有对焦

续航一样FZ100电池

由于FX30有散热风扇

续航算中等 

根据拍摄的强度

备用一些电池就行

总的来说 体积不大

没有取景器

4K120画质一般 但是有对焦

用起来还是比较方便 有翻转屏

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靳榕泽1228已知函数fx的定义域是[0,4],求函数fx2的定义域 -
支典刘18378178274 ______ 解由函数fx的定义域是[0,4], 在函数函数fx2中 所以0≤x²≤4 即0≤x≤2或-2≤x≤0 即-2≤x≤-2 即函数函数fx2的定义域{x/-2≤x≤-2}

靳榕泽1228已知函数y=fx的定义域为(0.1),求f(x^2)的定义域..急要 -
支典刘18378178274 ______[答案] y=fx的定义域为(0.1), 则f(x²)中0-1所以定义域(-1,0)∪(0,1)

靳榕泽1228已知f(3x - 2)的定义域为【 - 2,1】,求fx的定义域,问题答案尽量详细一点,谢谢
支典刘18378178274 ______ 已知f(3x-2)的定义域为【-2,1】,即-2 ≤ 3x-2 ≤1, -2 +2≤ 3x ≤1+2 ,0 ≤ 3x ≤3. 0≤ x ≤1,所以fx的定义域是[0.1].

靳榕泽1228已知函数fx的定义域是[0.1].求f(x的开方)的定义域 -
支典刘18378178274 ______ 函数f(x)的定义域是:[0,1] 即:f(x)中,x的取值范围是:0≤x≤1 则:f(x²)中,有:0≤x²≤1 也就是:x²≤1 得:-1≤x≤1 则: 函数f(x²)中,x的取值范围是:-1≤x≤1 即:函数f(x²)的定义域是:x∈[-1,1]

靳榕泽1228已知f3x的定义域是[a,b],求fx的定义域 才学抽象函数,完全没头绪啊,求解释~~具体. 谢谢. -
支典刘18378178274 ______ f(3x)的定义域是[a,b],所以,a<=x<=b3a<=3x<=3b 因此f(x)的定义域是[3a,3b]

靳榕泽1228已知fx的定义域为(2,4)求fx(x^2 - x)定义域 -
支典刘18378178274 ______ 解答:fx的定义域为(2,4) 即 f对(2,4)范围内的数有效,∴ 2<x²-x<4(1) x²-x>2 即 x²-x-2>0 ∴ x>2或x<-1(2) x²-x<4 即 x²-x-4<0 ∴ (1-√17)/2<x<(1+√17/2) 综上, (1-√17)/2<x<-1或2<x <(1-√17)/2 即函数的定义域为{x|(1-√17)/2<x<-1或2<x <(1-√17)/2}

靳榕泽1228已知函数f的定义域是,则函数fx的定义域是多少 -
支典刘18378178274 ______ 已知 f(x) 定义域为 【a,b】 则 f(x-1)定义域: aa+1

靳榕泽1228设fx的定义域是[0,1],求f(x²)的定义域 -
支典刘18378178274 ______ 解:因为x+a,x-a均在定义域上,0≤x+a≤1,a>0,-a≤x≤1-a 所以:a≤x≤1-a 区间[a,1-a]有意义,a≤1-a a≤1/2,又a>0,因此0<a≤1/2 所以:0<a≤1/2时,f(x+a)+f(x-a)的定义域为[a,1-a] 扩展资料 定义域的性质: 设x、y是两个变量,变量x的变化范围为D...

靳榕泽1228已知函数fx的定义域是[ - 2,4],求函数gx=fx+f - x的定义域 -
支典刘18378178274 ______ f(-x)定义域是【-4,2】 g(x)定义域取交集,得【-2,2】

靳榕泽1228fx的定义域为(a,b),求fx=f(3x - 1)+f(3x+1)的定义域 -
支典刘18378178274 ______ 3x-1,3x+1都在定义域上a<3x-1<(b+1)/3a<3x+1<(b-1)/3综上,得(a+1)/3<(b-1)/3...