python创建字典

汲怖削2164python字典赋值 -
邰忽爸15914958857 ______ 简单举个例子: dic = {'key':1,'key2':'str'} 赋新值例子: dic['key3'] = 0 dic['key4'] = 'sss' 替换现在值: dic['key'] = 2

汲怖削2164python向数据库插入字典,请问如何实现,谢谢! -
邰忽爸15914958857 ______ 数据库本身是不支持字典类型的(已知的绝大多数) 我以往的做法有两种:1. 把字典或者json格式数据作为字符串(string)直接插入,读取的时候再转换为字典.2. 为了避免某些字符,引号等转义问题发生,可以使用base64编码后导入数据库,读取时候再用base64解码

汲怖削2164如何将python遍历的数据保存成一个字典 -
邰忽爸15914958857 ______ #! /usr/bin/python # – * – coding:utf-8 – * - dictionary = {'a':'one','b':'two','c':'three'} #创建字典 dictionary1 = {1:'test1′,2:'test2′,3:'test3′} #创建字典 print dictionary,dictionary1 #打印输出字典 print dictionary['b'] #打印输出字典...

汲怖削2164python 字典列表值可能空如何建字典 -
邰忽爸15914958857 ______ data = dict() data[＂a＂] = 'v1' data[＂b＂] = 'v2' 如果没有c可以不赋值,也可以 data[＂c＂] = '' 取值时可以data.get(＂c＂, None)意思是如果存在c就返回值,不存在就返回None

汲怖削2164如果要用python写一本电话字典该怎么写 -
邰忽爸15914958857 ______ # please tall the detail of your question # maybe you can use a datatbase to do it # pip install django from django.db import models class Contact(models.Model): name = models.CharField(max_length=20) phone = models.CharField(max_length=20) address = models.CharField(max_length=255)

汲怖削2164Python:如何将字典中的值写入文件? -
邰忽爸15914958857 ______ yourDict={'1000':{'1':['a','b','c','d'],'2':['e','b','c','a']},'2000':{'1':['c','d','c','d'],'2':['a','a','c','d']}} out=open('out.xls','w') for key in yourDict: out.write(key) for key2 in yourDict[key]: out.write('\t') out.write(key2+'\t') out.write('\t'.join(yourDict[key][key2] )) out.write('\n'...

汲怖削2164python中,怎么做个字典,数句子中单词出现的次数 -
邰忽爸15914958857 ______ text = raw_input(＂enter a sentence:＂) words = text.split() wordscount = [words.count(elem) for elem in words] worddict={map(none,words,wordscount)} 要完成你的目标: 我要 计算每个词语出现的次数, 把词语出现的次数和词语列表组合成字...

汲怖削2164Python中关于字典的问题 -
邰忽爸15914958857 ______ import re from __future__ import print_function f=open(r'文件名') worddict={} for i,line in enumerate(f): words=re.findall(r'\w+',line) for word in words: worddict.setdefault(word,set()).add(i+1) for key,value in worddict.items(): print(key,end=＂:＂) print(','.join(sorted(value)))