巴西海军的圣保罗号航母，属于法国的克莱蒙梭级。该舰1960年下水，1963年正式进入法国海军服役。2000年，该舰在服役30多年以后，被转卖给巴西。

圣保罗号航母的舰首。该舰的标准排水量为24200吨，满载排水量为32800吨。

侧舷特写。按照巴西海军的计划，这艘舰艇将服役到2039年，也就意味着它的寿命会达到近80岁。注释：按照国际惯例，战舰下水命名即获得生命，因此通常按这个计算战舰的年龄。

使用的舰载机为A-4KU天鹰战斗机。天鹰战斗机在马岛战争中，曾经有非常优秀的表现。

3万吨和10万吨的对比，同里根号编队航行的圣保罗号航母。

航行途中的圣保罗号航母。该舰的最大航速可以达到32节，续航力为18节时13900千米。

A-4KU天鹰战斗机在圣保罗号航母上进行拦阻着舰。同从航母上起飞相比，着舰的危险性要大得多。

左右簇拥下的巴西海军圣保罗号航母

一架A-4KU天鹰战斗机停在圣保罗号航母的飞行甲板上。

阿根廷海军的S-2T型固定翼反潜机在圣保罗号上降落，看来两国没少举行联合演练。

干船坞中的圣保罗号航母。年纪大了，入坞接受修理是必不可少的。

从这里可以进入机库。

机库内部特写，虽然船儿只有3万多吨，同10万吨的核动力航母没法比，但看起来也比较宽敞。

舰岛后方特写

菲涅尔斯透镜系统，在舰载机着舰的时候，可以提供很大的帮助。

圣保罗号航母的舰岛，浓浓的法国风。

航母上的升降机，弹药和飞机就是通过这里运送到飞行甲板上的。

甲板上的一枚鱼雷，可能是给反潜直升机使用的。

圣保罗号航母上的机枪架子，配备的是勃朗宁重机枪，总共有4个这样的架子。

舰岛上方的电子设备，近处有个大圆球。

舰岛一角

该舰采用弹射起飞方式，图为蒸汽弹射器的导轨。

航行途中的圣保罗号航母，冒着浓浓的黑烟。

注意人与舰岛和飞机的对比。天鹰飞机是种小飞机，个头不大。

正在干船坞中接受维修的圣保罗号航母，由于比较老了，这艘船经常出海不到3个月就会回港接受维修。

除了天鹰以外，圣保罗号航母总共配备了39架飞机，包括图中的SH-3海王直升机。

正在进行起降作业的圣保罗号航母，该舰的员额为1920人，其中本舰有64名军官和1274名水兵，另外582人是空勤人员。巴西海军也想换船，可惜新买一条航母太花钱，只能姑且将就用着了。

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东殷芬4968s - 2t/3s*6s^2/s+2t=多少,(步骤要详细)
谭俩固18222342682 ______ s-2t/3s*6s^2/s+2t=s-2t/3s*6s+2t=s-4t+2t=s-2t

东殷芬4968s - t=5(1)5s+2t=15(2)方程组全过程 -
谭俩固18222342682 ______[答案] (1)*2+(2)得 2s-2t+5s+2t=10+15 7s=25 s=25/7 代入(1) 25/7-t=5 t=-10/7

东殷芬4968x+2y+xy=30求最大值,并求出此x.y的值 -
谭俩固18222342682 ______[答案] 采用换元法:另:t=xy,则:y=t/x原方程变为:x+2t/x+t=30x^2+2t+tx=30x^2表示平方.(2+x)t=30x-x^2t=[(-x^2)+30x]/(2+x)设s=2+x,则s>2x=s-2t=[-(s-2)^2+30(s-2)]/s=[-s^2-4+4s+30s-60]/s=[-s^2+34s-64]/s=-s+34-64/s=...

东殷芬4968a+b/a - b能不能约分,若能请给出详解 -
谭俩固18222342682 ______ a+b/a-b一般情况下不用约分,但是有的时候做一些推理题的时候可以化成a-b+2b/a-b=1+(2b/a-b) 或者是化成1+(2a/a-b).至于a²+2ab+b²/a²-b²=(a+b)²/(a+b)(a-b)=a+b/a-b.

东殷芬4968因式分解:(s - 2t)( - s - 2t) - (s - 2t)2. -
谭俩固18222342682 ______[答案] (s-2t)(-s-2t)-(s-2t)2 =4t2-s2-(s2+4t2-4st) =4st-2s2 =2s(2t-s)

东殷芬4968s=2t是一次函数吗 -
谭俩固18222342682 ______ 是的 这是正比例函数,也是一次函数

东殷芬49684s+3t=5 2s - t= - 5 要过程 -
谭俩固18222342682 ______ 解:4S+3T=5① 2S-T=-5② ①+②*3,得10S=-10 S=-1 代入①,得T=3 所以S=-1,T=3

东殷芬4968函数s=2t - t的平方,当t=多少时有最大值,最大值是什么 -
谭俩固18222342682 ______ S=2t-t^2 函数对称轴为t=1,故当t=1时,S有最大值1

东殷芬4968设数列{an}的首项a1=1,前n项和Sn满足关系是:3tSn - (2t+3)S(n - 1)=3t(t>0,n>=2) -
谭俩固18222342682 ______ 3+1/a(n-1)=(2t+3)/解:(1)∵3t*Sn-(2t+3)S(n-1)=3t ∴3t*S(n-1)-(2t+3)S(n-2)=3t 两式相减:3tSn-(5t+3)S(n-1)+(2t+3)S(n-2)=0 3t[Sn-S(n-1)]=(2t+3)[S(n-1)-S(n-2)] ∴an/3t ∴{an}是等比数列 (2)∵bn=3b(n-1)/2b(n-2)+3 ∴两边求倒:1/bn=2/b(n-1) ∴{1/bn}为公差2/3的等差数列 ∴bn=(2n+1)/

东殷芬4968一物体作直线运动,其运动方程为s=3t - t2,其中位移s单位为米,时间t的单位为秒,那么该物体的初速度为( ) -
谭俩固18222342682 ______[选项] A. 0米/秒 B. -2米/秒 C. 3米/秒 D. 3-2t米/秒