sin2x-cos2x化简公式

梁壮承1735化简:(1 sin2x - cos2x)/(1 sin2x cos2x) -
凌曹卖13862934285 ______ (1+sin2x-cos2x)/(1+sin2x+cos2x)=(2sin^2x +2sinxcosx)/(2cos^2x+2sinxcosx)=2sinx(sinx+cosx)/2cosx(cosx+sinx)=tanx

梁壮承1735一道简单的函数化简题1+sin2x - cos2x 要过程~ -
凌曹卖13862934285 ______[答案] 1+sin2x-cos2x =1+2sinxcosx-(1-2sin方x) =2sinxcosx+2sin方x =2sinx(sinx+cosx)

梁壮承1735cos2x - sin2x化简为一角一函数怎么化? -
凌曹卖13862934285 ______ cos2x-sin2x =√2*(cos2x*√2/2 - sin2x*√2/2) =√2*[cos2x*cos(π/4) - sin2x*sin(π/4)] =√2*cos(2x+ π/4)

梁壮承1735sin2x - cos2x - 1=√2 sin(2x - π/4) 这又是怎么化的? -
凌曹卖13862934285 ______[答案] sin2x-cos2x-1 =√2(sin2x*√2/2-cos2x*√2/2)-1 =√2sin(2x-π/4)-1 如果本题有什么不明白可以追问,

梁壮承17351 - sin2x - cos2x怎么化简成就sin什么的形式 -
凌曹卖13862934285 ______[答案] 1-sin2x-cos2x =1-2sinxcosx-(1-2sin²x) =2sin²x-2sinxcosx =2sinx(sinx-cosx) =2√2sinx(sinxcos45°-cosxsin45°) =2√2sinxsin(x-45°)

梁壮承1735函数y=sin2x - cos2x的最小正周期是______. -
凌曹卖13862934285 ______[答案] y=sin2x-cos2x= 2( 2 2sin2x− 2 2cos2x)= 2sin(2x- π 4) ∴T= 2π 2=π 故答案为:π

梁壮承1735关于三角函数化简
凌曹卖13862934285 ______ f(x)=√3sin2x-cos2x=2(√3/2sin2x-1/2cos2x)=2(cosπ/6sin2x-sinπ/6cos2x)=2sin(2x-π/6)

梁壮承1735化简三角函数:y=sin2x - cos2x -
凌曹卖13862934285 ______ 根号2倍Sin(2X-π÷4) 周期为π 最大值为根号2

梁壮承1735f(x)=√3sin2x﹣cos2x化简式(求过程)
凌曹卖13862934285 ______ f(x)=√3sin2x-cos2x =2(√3/2sin2x-1/2cos2x) =2(cos(π/6)sin2x-sin(π/6)cos2x) =2sin(2x-π/6)满意请采纳,谢谢

梁壮承1735sin2x+cos2x化简~ -
凌曹卖13862934285 ______ 解:由辅助角公式,sin2x + cos2x = sin(2x + π/4) .