sin2x-cos2x化简过程

沙变建5042请化简一下这个三角函数式2cosx(sinx - cosx)+1,参考答案sin2x - cos2x,教教我吧,不太急, -
单官柄13049726717 ______[答案] 1.去括号,把2cosx乘进去 原式=2cosx*sinx-2cosx*cosx+1 2.由2sinx*cosx=sin2x 及 2cosx*cosx-1=cos2x 化简 上式=sin2x-cos2x-1+1 =sin2x-cos2x 倍角公式: sin(2α)=2sinα·cosα=2/(tanα+cotα) cos(2α)=cos^2(α)-sin^2(α)=2cos^2(α)-1=1-2sin^2(α) tan(2α)...

沙变建5042cos2x - sin2x化简为一角一函数怎么化? -
单官柄13049726717 ______ cos2x-sin2x =√2*(cos2x*√2/2 - sin2x*√2/2) =√2*[cos2x*cos(π/4) - sin2x*sin(π/4)] =√2*cos(2x+ π/4)

沙变建5042sin2x - cos2x=2 求 x? -
单官柄13049726717 ______ 和差化积公式:sin2x-cos2x=2 sin2x+sin(2x-π/2)=22*sin(2x-π/4)cos(π/4)=2 sin(2x-π/4)=根号2 无解

沙变建5042一道简单的函数化简题1+sin2x - cos2x 要过程~ -
单官柄13049726717 ______[答案] 1+sin2x-cos2x =1+2sinxcosx-(1-2sin方x) =2sinxcosx+2sin方x =2sinx(sinx+cosx)

沙变建5042化简:(1 sin2x - cos2x)/(1 sin2x cos2x) -
单官柄13049726717 ______ (1+sin2x-cos2x)/(1+sin2x+cos2x)=(2sin^2x +2sinxcosx)/(2cos^2x+2sinxcosx)=2sinx(sinx+cosx)/2cosx(cosx+sinx)=tanx

沙变建5042sin2x - cos2x为什么等于????? -
单官柄13049726717 ______ 通过配方啊!先提出个根号2出来,然后sin2x和cos2x前面都有个2分之根号2了,sin和cos四分之派都是2分之根号2啊!然后简单配方就可以得到了..

沙变建5042速求化简cos2x - sin2x的值 -
单官柄13049726717 ______[答案] =√2(cosπ/4cos2x-sinπ/4sin2x) =√2cos(π/4+2x)

沙变建5042求化简这个式子:f(x)=sin2x - cos2x 求速度.... -
单官柄13049726717 ______ f(x)=sin2x-cos2x =√2(sin2x*cosπ/4-cos2x*sinπ/4) =√2sin(2x-π/4 )不明白,可以追问如有帮助,记得采纳,谢谢 祝学习进步!

沙变建5042急! - 一道高中数学题化简:(sin2x - cos2x+1)/(1
单官柄13049726717 ______ (sin 2x - cos 2x +1)/(1 + cot x) =[2sinxcosx+2(sinx)^2/(1+cotx) =2sinx(sinx+cosx)/[(sinx+cosx)/cosx] =2sinxcosx=sin2x

沙变建5042f(x)=√3sin2x﹣cos2x化简式(求过程)
单官柄13049726717 ______ f(x)=√3sin2x-cos2x =2(√3/2sin2x-1/2cos2x) =2(cos(π/6)sin2x-sin(π/6)cos2x) =2sin(2x-π/6)满意请采纳,谢谢