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sinxdx+dcosx

来源:baiyundou.net   日期:2024-08-23

郗施眉2653sin4次方的不定积分怎么求 -
艾汪达17556325290 ______ ∫(sinx)^4dx =∫[(1/2)(1-cos2x]^2dx =(1/4)∫[1-2cos2x+(cos2x)^2]dx =(1/4)∫[1-2cos2x+(1/2)(1+cos4x)]dx =(3/8)∫dx-(1/2)∫cos2xdx+(1/8)∫cos4xdx =(3/8)∫dx-(1/4)∫cos2xd2x+(1/32)∫cos4xd4x =(3/8)x-(1/4)sin2x+(1/32)sin4x+C 扩展资料: 设F(x)是函数f(x)...

郗施眉2653为什么∫ f(cosx)sinxdx= - ∫ f(cosx)dcosx -
艾汪达17556325290 ______ 因为(cosx)'=-sinx 所以dcosx=(cosx)'dx=-sinxdx 由此可知sinxdx=-dcosx 就是根据这个从sinxdx凑出-dcosx的

郗施眉2653∫(sinx)^3/(cosx)^6dx -
艾汪达17556325290 ______ 用有理代换 sinxdx=-d(cosx) 再把剩下的sinx都化为cosx1/5*sin(x)^4/cos(x)^5+1/15*sin(x)^4/cos(x)^3-1/15*sin(x)^4/cos(x)-1/15*sin(x)^2*cos(x)-2/15*cos(x)

郗施眉2653sinx的三次方dx的积分怎么求? -
艾汪达17556325290 ______ sinx的三次方dx的积分是1/3cos³x-cosx+C ∫sin³xdx =∫sin²x*sinxdx =∫(1-cos²x)d(-cosx)陵睁或 =-∫(1-cos²x)dcosx =-∫1dcosx+∫cos²xdcosx =-cosx+1/3cos³x+C =1/3cos³x-cosx+C 扩展资料: 积分的求解:F(x)是函数f(x)的一个原函数,我们把...

郗施眉2653x^6*sinx的不定积分怎么求? -
艾汪达17556325290 ______[答案] ∫x^6sinxdx =-∫x^6dcosx = - x^6cosx +6∫x^5cosxdx =- x^6cosx +6∫x^5dsinx =- x^6cosx +6x^5sinx -30∫x^4sinxdx =- x^6cosx +6x^5sinx +30∫x^4dcosx = - x^6cosx +6x^5sinx +30x^4cosx -120∫x^3cosxdx =- x^6cosx +6x^5sinx +30x^4cosx -120∫x^3dsinx =- ...

郗施眉2653sinx^ - 1的积分怎么算 -
艾汪达17556325290 ______[答案] ∫1/sinxdx =∫sinx/sin^2xdx =-∫1/sin^2xdcosx =-∫1/(1-cos^2x)dcosx =-∫1/[(1-cosx)+1/(1+cosx)]dcosx =ln(1-cosx)-ln(1+cosx)+C

郗施眉2653数学:d(cosx+x的平方)=?
艾汪达17556325290 ______ d(cosx+x^2) =dcosx+dx^2 =-sinxdx+2xdx =(2x-sinx)dx

郗施眉2653y=xsin2x+cosx的微分 -
艾汪达17556325290 ______[答案] dy=d(xsin2x)+dcosx =sin2xdx+xdsin2x-sinxdx =sin2xdx+xcos2xd2x-sinxdx =sin2xdx+2xcos2xdx-sinxdx =(sin2x+2xcos2x-sinx)dx

郗施眉2653∫(sinx/cos立方x)dx -
艾汪达17556325290 ______ ∫(sinx/cos立方x)dx =-∫(d(cosx)/cos立方x) =(-1/2)*1/cos^2x+c

郗施眉2653求∫(1+sinx)/[sinx(1+cosx)]dx拜托了各位 谢谢 -
艾汪达17556325290 ______ ∫(1+sinx)/[sinx(1+cosx)]dx =∫1/[sinx(1+cosx)]dx+ ∫1/(1+cosx)dx =∫sinx/[sin^2x(1+cosx)]dx+ ∫(1-cosx)/(1-cos^2x)dx =-∫1/[(1-cos^2x)(1+cosx)]dcosx+ ∫(1/sin^2xdx- ∫1/sin^2xdsinx =-∫1/[(1-cosx)(1+cosx)^2]dcosx-ctnx+1/sinx =-∫1/[(1-cosx)(1+cosx)^2]...

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