sql分组统计求和
景凭新3028sql 分组求和 同时满足2个条件,再把求和结果相加 -
富询垂17870018544 ______ 用 union 做多查询连接 SELECT A, SUM(real_qty) AS qiuhe, B FROM AA GROUP BY A, B HAVING (B = '小明') ORDER BY item_barcode union SELECT A, SUM(real_qty) AS qiuhe, B FROM AA GROUP BY A, B HAVING (B = '小 花') ORDER BY item_barcode union SELECT ''as a, SUM(real_qty) AS qiuhe, '' as b FROM AA GROUP BY A, B
景凭新3028sql 分类求和? -
富询垂17870018544 ______ 分类求和需要用sun函数.1、如emp表中数据如下:2、现要按照deptno字段分组,求每个分组下的sal的和,可用如下语句:select deptno,sum(sal) from emp group by deptno;3、执行结果:
景凭新3028求SQL语句分组求和,求各经销商每个产品总个数 -
富询垂17870018544 ______ select 产品编号,经销商,sum(库存) as 库存 from 表 group by 产品编号,经销商 order by 经销商
景凭新3028如何得到SQL查询总和 -
富询垂17870018544 ______ SELECT SUM(A.COL) FROM A;--求具体那一列的和值 SELECT COUNT(1) FROM A;--求查询结果总数
景凭新3028Sql分组求和问题 -
富询垂17870018544 ______ SELECT A,SUM(B),SUM(C),SUM(D) FROM N GROUP BY A
景凭新3028sql server 分类求和 -
富询垂17870018544 ______ select case when code in('1') then '检查费' when code in ('2','5','7') then '化验' when code in( '4') then '其他' end+ convert(varchar,sum(case when code in('1') then charge when code in ('2','5','7') then charge when code in('4') then charge end)) from ...
景凭新3028用sql 如何实现 报表的分组的小计,合计!最后还有一个总计 -
富询垂17870018544 ______ 如果要使用SQL来实现的话,可以采用临时表,但是这样必然会牺牲效率.SELECT * INTO #TEMP FROM 表 INSERT INTO #TEMP VALUES(....) --这一句是你的小计、合计、总计 SELECT * FROM #TEMP 过程基本如此,需要注意的是临时表字段的类型,如果出现某字段不允许为空的话,可以采用如下语句来变更字段类型:ALTER TABLE #TEMP ALTER COLUMN 字段名 类型 NULL 最后要注意的是排序,要使得小计、合计、总计在结果集的最后.
景凭新3028每个月份分组统计求和 group by -
富询垂17870018544 ______ create table table6 (时间 datetime,金额 money) select * from table6 insert table6 select '2007.11.12', 100 insert table6 select '2007.11.13', 200 insert table6 select '2007.12.01', 400 select substring(convert (char ,时间,112),5,2) as 月份, sum (金额) as 汇总金额 from table6 group by (substring(convert (char ,时间,112),5,2))
景凭新3028sql 查询多张表的分数总和 -
富询垂17870018544 ______ select a.name,sum(a.pri+b.pri)as price from (select name,sum(price) as pri from Mainboard group by name ) as a inner join ( select name,sum(price) as pri from ems group by name ) as b on (a.name = b.name) group by a.name order by price desc
景凭新3028SQL 两次分组求百分比 -
富询垂17870018544 ______ select order_type,is_olduser,sum(counts)/c2 from order_today lett join (select order_type ot,sum(counts) c2 from group by order_today) ot2 on ot2.ot=order_today.order_type group by order_type,is_olduser,c2