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tan10°怎么算

来源:baiyundou.net   日期:2024-08-22

作者:大哥就是大哥

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宓滢林1128sin40°sec10° - √3/2tan10°怎么算,有详细过程,谢谢! -
蒋善昌17135444890 ______[答案] sin40sec10- √3/2tan10 =sin40/cos10-cos30sin10/cos10 =(sin(30+10)-cos30sin10)/cos10 =(sin30cos10+cos30sin10-cos30sin10)/cos10 =sin30cos10/cos10 =sin30=1/2

宓滢林1128怎么计算:tan10·tan20+tan10·tan60+tan20·tan60= -
蒋善昌17135444890 ______ tan10(tan20+tan60)+tan20tan60=tan10tan80(1-tan20tan60)+tan20tan60=(1-tan20tan60)+tan20tan60=1

宓滢林1128tan10°化成sin80°的过程 -
蒋善昌17135444890 ______ tan10°=sin10°/cos10° =sin(90°-80°)/cos(90°-80°) =(sin90°cos80°-sin80°cos90°)/(cos90°cos80°+sin90°sin80°) =cos80°/sin80°

宓滢林1128tan100度=t,tan80度= - t,tan10度= - 1/t -
蒋善昌17135444890 ______[答案] 三角函数诱导公式 tan80=-tan(180-80)=-tan100=-t; tan10=cot(90-10)=cot80=1/tan80=-1/t

宓滢林1128tan10度tan20度tan30度...tan70度tan80=多少 -
蒋善昌17135444890 ______[答案] 用到公式tanx*tan(90-x)=1下面证明这个公式tan(90-x)=sin(90-x)/cos(90-x)=cosx/sinx=1/tanx公式可以直接用,而且不难记,是吧~所以题目=(tan10*tan80)*(tan20*tan70)*(tan30*tan60)*(tan40*tan50)=1*1*1*1=1...

宓滢林1128化简tan10度tan20度+tan20*tan60度+tan60度+tan10度 -
蒋善昌17135444890 ______ 应该是tan10度*tan20度+tan20*tan60度+tan60度*tan10度 tan30度=√3/3=tan(10+20)=(tan10+tan20)/(1-tan10tan20) 所以(√3-√3tan10tan20)/3=tan10+tan20 tan60=√3所以原式=tan10tan20+√3tan10+√3tan20 =tan10tan20+√3(tan10+tan20) =tan10tan20+√3*(√3-√3tan10tan20)/3 =1

宓滢林1128tan20度等于多少谢谢这位老师了. -
蒋善昌17135444890 ______[答案] tan(10度) = 0.176326981 tan(15度) = 0.267949192 tan(20度) = 0.363970234 tan(30度) = 0.577350269 tan(60度) = 1.73205081

宓滢林1128麻烦告诉一下tan5°、tan10°、tan15°、tan20°、tan25°、tan30°、tan35°、tan40°、tan45°的值 -
蒋善昌17135444890 ______[答案] tan(5°) = 0.08748866352592 tan(10°) = 0.17632698070846 tan(15°) = 0.26794919243112tan(20°) = 0.3639702342662 tan(25°) = 0.466307658155 tan(30°) = 0.57735026918963 tan(35°) = 0.70020753820971 t...

宓滢林1128【急】4sin10°+根号3tan10°怎么算? -
蒋善昌17135444890 ______ sin10° 约等于0.17364,tan10°约等于0.176334sin10°+根号3tan10°=4X0.17+根号3X0.18=0.992

宓滢林1128计算:tan10°·tan20°·tan40°·tan50°·tan70°·tan80°(要详细的 -
蒋善昌17135444890 ______ tan10°·tan80°=1 tan20°·tan70°=1 tan40°·tan50°=1 ∴原式=1

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