tan2α怎么求

刘咽季4802若tanα=2,则tan2α=______. -
顾蓝皆15749226611 ______[答案] 因为tanα=2 所以tan2α= 2tanα 1−tan2α= 2*2 1−22=- 4 3 故答案为:- 4 3

刘咽季4802已知tanα= - 3,求tan2α的值 -
顾蓝皆15749226611 ______ 直接套公式 tan2α=2tanα/(1-tan²α)=2/3

刘咽季4802已知cosα= - 1/3,且α属于(π/2,π),求tan2α的值 -
顾蓝皆15749226611 ______[答案] ∵α属于(π/2,π) ∴sinα>0 ∵cosα=-1/3 ∴sinα=√[1-(cosα)^2]=2√2/3 则tanα=sinα/cosα=-2√2 故ta(2α)=2tanα/[1-(tanα)^2] (应用倍角公式) =4√2/7.

刘咽季4802tanα=1/2,tan2α是多少? -
顾蓝皆15749226611 ______[答案] tan2α=tan(α+α)=(tanα+tanα)/(1-tanαtanα) ∵tanα=1/2,∴tan2α=(1/2+1/2)/[1-(1/2)(1/2)]=1/(1-1/4)=4/3

刘咽季4802数学公式tan2α= -
顾蓝皆15749226611 ______ tan2α=2tanα/(1-tanα^2)

刘咽季4802求tan2α,在线等答案
顾蓝皆15749226611 ______ sinα=3/5,α∈(π/2,π), 所以cosa=-4/5 tana=-3/4 tan2a=2tana/(1-tanatana) =-24/7

刘咽季4802(数学)求tan2β -
顾蓝皆15749226611 ______ tan2β =tan[(α+β)-(α-β)] =[tan(α+β)-tan(α-β)]/[1+tan(α+β)*tan(α-β)] =(1/4-2/5)/(1+1/4*2/5) =-3/22

刘咽季4802已知tan2α=⅓,求tanα的值 -
顾蓝皆15749226611 ______[答案] tan2α=1/3 2tana/(1-tana^2)=1/3 6tana=1-tana^2 tana^2+6tana-1=0 tana=[-6+/-根号(40)]/2 =-3+/-根号10

刘咽季4802数学问题 知道tanα如何求tan2α -
顾蓝皆15749226611 ______ tan2α=(2tanα)/(1-tan^2α)

刘咽季4802tan2α=1/3求tanα=?
顾蓝皆15749226611 ______ tan2α=1/3 2tana/(1-tana^2)=1/3 6tana=1-tana^2 tana^2+6tana-1=0 tana=[-6±√40]/2 =-3±√10