tan35+12

汲砌岸3060tan35π/12 怎么写 .. 帮帮忙..
后卞莲17150633495 ______ 先把35牌/12换成2牌加11牌/12.然后把11牌/12换成5牌/6加个1牌/12.十二分之一牌再用tan1/6求出.

汲砌岸3060利用和差公式求函数值 sin ( - 7π/12). cos ( - 61π/12) tan 35π/12 -
后卞莲17150633495 ______ 解:sin(-7/12)=sin(5π/12-π)=-sin(π-5π/12)=-sin5π/12=sin(3π/12+2π/12). =-sin(π/4+π/6)=-(sinπ/4cosπ/6+cosπ/4sinπ/6)=-[(√2/2*√3/2+√2/2*(1/2)] = -(√6+√2)/4. cos(-61π/12)=cos61π/12=cos[12*5π+π)/12=cos(5π+π/12)=cos(4π+(π+π/12]. =-cos(π+π/...

汲砌岸3060求tan 35°+tan 25°+√3tan 35°tan25°的值. 请给出详细的解释,谢谢!! -
后卞莲17150633495 ______ tan60° = tan(35° + 25°) = (tan 35° + tan 25°)/(1 - tan35°tan25°) = √3 所以 tan 35° + tan 25° = √3(1 - tan35°tan25°) = √3 - √3tan35°tan25° 所以 tan 35° + tan 25° + √3tan 35°tan25° = √3 - √3tan35°tan25° + √3tan35°tan25° = √3

汲砌岸3060tan15tan35+tan35tan40+tan40tan15详细过程
后卞莲17150633495 ______ 首先计算tan15=2-√3, tan75=tan(35+40)=2+√3=(tan35+tan40)/1-tan35tan40 所以 tan35+tan40=(2+√3)(1-tan35tan40) 解:原式=tan15(tan35+tan40)+tan35tan40 =(2-√3)(2+√3)(1-tan35tan40)+tan35tan40 =1-tan35tan40+tan35tan40=1 你看对不对

汲砌岸3060tan35度约等于多少
后卞莲17150633495 ______ tan35度=0.70021 =tan7π/36=tan0.6108652=0.70021

汲砌岸3060一到高中数学题tan10+tan35+tan10tan35等于多少.都是角度制的 -
后卞莲17150633495 ______[答案] tan45=1 所以tan(35+10)=(tan35+tan10)/(1-tan10tan35)=1 tan35+tan10=1-tan10tan35 tan35+tan10+tan10tan35=1

汲砌岸3060tan35度约等于多少 -
后卞莲17150633495 ______ tan(35°) = 0.70020753820971 约等于0.7

汲砌岸3060三角函数tan15tan35+tan35tan40+tan40tan15=? -
后卞莲17150633495 ______[答案] tan15tan35+tan35tan40+tan40tan15=tan15tan35+tan40(tan15+tan35)=tan15tan35+cot50(tan15+tan35) 因为cot50=1/tan... tan50=(tan15+tan35)/(1-tan15tan35), 所以cot50=(1-tan15tan35)/(tan15+tan35) 故tan15tan35+cot50(tan15+tan35)=tan15tan...

汲砌岸3060利用和(差)角公式求三角函数值cos( - 61π/12)tan(35π/12) -
后卞莲17150633495 ______[答案] cos(-61π/12)=cos(6π-11π/12)=cos(-11π/12)=-cos15度=-cos(60-45)=-(cos60cos45+sin60sin45)=-(根号6+根号2)/4 tan同理也这样做

汲砌岸3060利用和(差)角公式求三角函数值sin( - 7π/12)cos( - 61π/12)tan(35π/12) -
后卞莲17150633495 ______[答案] sin(-7π/12)=-sin(7π/12) =-sin(3π/12+4π/12)=-[sin(π/4)cos(π/3)+cos(π/4)sin(π/3)]=-1/4(2^(1/2)+6^(1/2)) cos(-61π/12)= cos(61π/12)= cos(5π+ π/12)=cos(π+π/12)=-cos(π/12) -cos(4π/12-3π/12)=-(cos(π/3)cos(π/4)+sin(π/3)sin(π/4)) =-((1/2)(2^(1/2)/2)+3^(1/2)/2*(...