作者：逸行风

      头阵子帮朋友装机的时候用到了这块索泰的RTX 4070Ti-12GB X-GAMING OC显卡，分享一下啦。

官方主要参数图如上。

开箱特写

    开箱动图来一张。

          索泰RTX 4070Ti-12GB X-GAMING OC显卡是3风扇设计，抢眼的使用了蓝白相间的海浪配色外壳，风扇扇叶官方命名是暗影疾风扇叶，通过优化扇叶曲率，提升扇叶表面光滑度，减少空气摩擦和风噪，提升风量风压，而且支持智能启停，降噪效果MAX。

       侧面来一张，蓝白相间的外壳围绕着索泰的Logo，通电后有灯效，还可以通过索泰最新的FireStorm 4.0显卡管控软件来对灯效进行设置（这个软件可不止能够控制灯效，还能够调节显卡核心频率、显存频率、电压、风扇转数、风扇曲线调整等运行参数），不过旁边的GEFORCE RTX就没有这个待遇啦。
      供电接口是采用了最新的16Pin接口，需要支持ATX 3.0规格的电源，当然，索泰也随显卡附送了3*8Pin转16Pin的供电转接线，老电源也不用担心，只是多接一根线。

       金属背板已经是传统艺能了，右侧的对流穿透散热孔位采用了全新设计，整体设计的很nice，涂鸦样的X-GAMING和底纹，覆盖了整个背板，非常亮眼。

     输出接口为3DP1.4a，1HDMI 2.1。

侧面再来一张，可以看到厚重的镀镍散热鳍片模组。

 暗影疾风扇叶再来张特写，依稀能看到下面的冰脉2.0复合热管。

测试

朋友的主机配置为CPU：AMD 7600X，主板：华擎B650E PG-itx主板，内存：Kingston FURY Beast野兽RGB灯条（16GB*2,6000MT/s）。

3DMARK Time Spy测试，分数19198，显卡分数23133，CPU分数9776。

3DMARK Time Spy Extreme测试，分数9204，显卡分数10982，CPU分数4801。

3DMARK Fire Strike测试，分数39097，显卡分数53644，物理分数27875，综合分数16091。

3DMARK Fire Strike Extreme测试，分数24330，显卡分数26299，物理分数27813，综合分数13911。

3DMARK Fire Strike Ultra测试，分数13315，显卡分数13305，物理分数27912，综合分数7486。

3DMARK PORT ROYAL测试，显卡分数14266。

DLSS测试也跑了一下。

众生平等奥德赛，2K分辨率，画质极高，平均帧率126。

孤岛惊魂5，2K分辨率，画质极高，平均帧率165。

古墓丽影：暗影，2K分辨率，设置如上，平均帧率197。

古墓丽影：暗影，2K分辨率，设置如上，平均帧率131。

古墓丽影：暗影，2K分辨率，将抗锯齿由SMAA2提高到SMAA4，平均帧率101。

荒野大镖客2，设置如上，平均帧数123.239。

荒野大镖客2，设置如上，平均帧数122.685，虽然平均帧看起来没有怎么降低，但是最高帧降了20多。

赛博朋克2077，2K分辨率，选择快速预设方案-光线追踪：超级，平均帧数124.65。

吃鸡2K分辨率，整体图像设置如上图，帧率在170帧-210帧浮动。

     这块索泰的RTX 4070Ti-12GB X-GAMING OC显卡完全能够满足3A大作在2K-144高刷显示器上的需求，还能够有富裕，还是很不错的，收工~ 

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云睿明4157对曲线x^4+y^2=1的图像,有下面四个命题:①关于x、y轴对称;②有且只有一个对称中心;③封闭且面积大于π④封闭且面积小于π,其中正确的序号是 -
臧瑾变17050401744 ______[答案] 这个题目正确的答案是:①关于x、y轴对称;②有且只有一个对称中心;③封闭且面积大于π 主要是③的理由,由题知0≤x≤1,因此x^4≤x,因此圆向外凸,因此面积大于π

云睿明4157怎样用MATLAB画隐函数 x^4+y^2=1 的图像 -
臧瑾变17050401744 ______ ezplot('x^4+y^2-1') ezplot('x.^4+y.^2-1')两种方法都可以默认绘制范围-2Pi,2Pi

云睿明4157如何用matlab画出函数y=(1/3)*x^4/(4+x^4)的图像? -
臧瑾变17050401744 ______ x=0:1:10; y=(1/3)*x^4/(4+x^4); plot(x,y)

云睿明4157函数Y=X^4/3的图像 是与y=x^3一样还是与y=x^2一样? -
臧瑾变17050401744 ______[答案] 这三个不是一个函数,图像不可能一样的.如果是特点的话,就和y=x^2相似,都是关于y轴对称的偶函数

云睿明4157Y=X^(2/4)图象? -
臧瑾变17050401744 ______ 有 Y=X^(2/4)和Y=X^(1/2)定义域不同前者为全体实数 后者为大于等于零的实数值域 都一样

云睿明4157x^4+ax^3+bx^2+cx+d 可能的图像为? -
臧瑾变17050401744 ______ y=x^4+ax^3+bx^2+cx+d=x^4(1+a/x+b/x^2+c/x^3+d/x^4) x趋近正无穷或者负无穷,a/x,b/x^2,c/x^3,d/x^4都趋于0,那么(1+a/x+b/x^2+c/x^3+d/x^4)趋于1.x^4趋于正无穷 所以y不论x趋于正无穷还是负无穷,y都趋于正无穷

云睿明4157高次多项式函数怎么画例如y=(x - 5)(x=3)^4(x^2+6)大致图像 -
臧瑾变17050401744 ______[答案] y=(x-5)(x-3)^4(x^2+6)图像如图:与x轴交点为(5,0),(3,0), 与y轴交点为(0, -2430)其它还需要求的就是单调性,极值点,拐点,渐近线等.

云睿明4157y^2= - x^4+16的图像怎么画如何根据y= - x^4+16画y^2= - x^4+16的图像? -
臧瑾变17050401744 ______[答案] 把 y=-x^4+16 的函数值开平方即可描点绘出 y²=-x^4+16 的图像.后者的定义域是 [-2,2],值域是 [-4,4],因此图像限制在此范围内.图像如下图所示:

云睿明4157“x^4+y^2=1的图像是一个封闭图形,且面积大于π.为什么? -
臧瑾变17050401744 ______[答案] 对的 相对于x^2+y^2=1 是圆面积是π x^4次方 由于x区间绝对值是小于1的 所以能在使得2式中相同X时 x^4 要更小 Y能取的更大些 应该就是x^2+y^2=1 这个圆的基础上 往上拉了点的椭圆

云睿明4157y=x^1/4图像 -
臧瑾变17050401744 ______[答案] 如图,