y+ln+1-x

屈空环3287f(x)是R上的奇函数,当x≥0时,f(x)=x^3+ln(1+x)则当x<0时,f(x)= 答案 -
蒯行晨17016044573 ______ f(x)是R上的奇函数.当x≧0时,f(x)=x³+ln(1+x),则当x<0时f(x)=?解:作函数F(x,y)=y-x³-ln(1+x)=0,因为F(x,y)是奇函数,所以F(-x,-y)=F(x,y); 于是F(-x,-y)=-y+x³-ln(1-x)=0, 移项得y=x³-ln(1-x)【x<0】.可以作个验证:f(1/2)=1/8+ln(3/2);f(-1/2)=-1/8-ln(3/2)=-[1/8)+ln(3/2)]=-f(1/2).故结论正确·.

屈空环3287常微分方程:y'=1 - x+y - xy求具体过程,谢谢! -
蒯行晨17016044573 ______ y'=1-x+y(1-x)=(1-x)(1+y) dy/(1+y)=(1-x)dx ln(1+y)=x-x^2/2+c y=e^(x-x^2/2+c)-1

屈空环3287y=in((1 - x)/(1+x))求导 -
蒯行晨17016044573 ______ y'=1/[(1-x)/(1+x)]*[(1-x)/(1+x)]'=(1+x)/(1-x)*[2/(1+x)-1]'=(1+x)/(1-x)*2*(-1)(1+x)^(-2)=-2/(x+1)(1-x)=2/(x+1)(x-1)

屈空环3287[ln(x+1) - lnx]的导数 -
蒯行晨17016044573 ______ 解法1:[ln(x+1)-lnx]'=[ln(x+1)]'-(lnx)'=1/(x+1)-1/x=x/[x(x+1)]-(x+1)/[x(x+1)]=[x-(x+1)]/[x(x+1)]=(x-x-1)/[x(x+1)]=-1/[x(x+1)]

屈空环3287求导:y=1 - ln x/1+ln x 求过程谢谢. -
蒯行晨17016044573 ______ 公式:(u/v)'=(u'v-uv')/v² 应用公式得到: y'=[(1-lnx)'(1+lnx)-(1-lnx)(1+lnx)']/(1+lnx)² =[(-1/x)·(1+lnx)-(1-lnx)·1/x]/(1+lnx)² =-2/[x(1+lnx)²]

屈空环3287ln的绝对值1+y等于多少?怎么算? -
蒯行晨17016044573 ______ ln的绝对值1+y等于多少 ln|1+y| 当y=0时 ln|1+y|=0 当y=-1时无意义 当y>-1 ln|1+y|=ln(1+y) 当yln|1+y|=ln(-1-y)

屈空环3287y=ln根号[(x+2)(x+3)/x+3]求导 -
蒯行晨17016044573 ______ 题目是不是 y=ln√[(x+2)(x+3)/x+3] 的意思?如果是,那么先整理得 y=ln√[(x+2)(1+3/x)+3]=ln√[x+2+3+6/x+3]=ln√[x+8+6/x]=ln√[(1/x)(x+2)(x+4)]=(1/2)[ln(1/x)+ln(x+2)+ln(x+4)]=(1/2)[-lnx+ln(x+2)+ln(x+4)] 求导,则 y'=(1/2)[-1/x+1/(x+2)+1/(x+4)]=(x-2)/[x(x+4)]

屈空环3287设y=ln根号下1 - x/1+x,则y''为多少 -
蒯行晨17016044573 ______[答案] y=ln根号下1-x/1+x=0.5ln(1-x)-0.5ln(1+x)y'=0.5/(1-x) - 0.5/(1+x)=0.5(1+x-1+x)/(1-x)(1+x)=x/(1-x²)y''=(1-x²)+2x²/(1-x²)²=(1+x²)/(1-x²)²

屈空环3287函数y=ln(1 - x)除以(1+x),则y''(0) -
蒯行晨17016044573 ______[答案] y = (1+x)⁻¹ln(1-x) y' = (-1)(1+x)⁻²ln(1-x) + (1+x)⁻¹ (1-x)⁻¹(-1) = -(1+x)⁻²ln(1-x) - (1-x²)⁻¹ y'' = -(-2)(1+x)⁻³ln(1-x) - (1+x)⁻²(1-x)⁻¹(-1) - (-1)(1-x²)⁻²(-2x) = 2(1+x)⁻³ln(1-x) + (1+x)⁻²(1-x)⁻¹ -2x(1-x²)⁻² x = 0,y'' = 2(1+0)⁻³ln(1...

屈空环3287求导数y=ln根号[(1 - x)/(1+x)] -
蒯行晨17016044573 ______ ln根号[(1-x)/(1+x)] y'=(1+x)/(1-x)*[(-1-x-1+x)/(1+x)^2]=-2/(1-x^2)