导数五步法画函数图像10个函数示意图应用举例之一
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1.函数y=(12x2+9)(4x2+14)的图像示意图：介绍函数的定义域、单调性、凸凹性、极限等性质及五点图表，并通过导数知识计算函数的单调和凸凹区间，简要画出示意图。
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2.函数y=(19x2+5)√(4x2+9)的主要性质及其图像：介绍函数的定义域、单调性、凸凹性、极限等性质，列举函数的五点图表，进一步画出函数的示意图。
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3.函数y=4√(x+80)^7图像画法及步骤：本文通过函数的定义、单调、凸凹性和极限等性质，介绍函数的主要性质及图像画法步骤。
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4.曲线x³+y³=2的主要性质及其图像示意图：介绍曲线方程的定义域、单调性、凸凹性等性质，同时用导数的知识求解函数的单调区间和凸凹区间，并简洁画出函数的图像示意图。
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5.√(x+4)+√(3y+5)=2的图像示意图：介绍曲线方程的定义域、单调性、凸凹性及极限等性质，同时用导数简洁画出函数的图像示意图。
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6.函数y=16x3+8x的图像示意图及主要性质：介绍函数的定义域、单调性、凸凹性、极限等性质，列举函数的五点图表，进一步画出函数的示意图。
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7.函数y=√(20x-87)^5图像画法及步骤：通过函数的定义、单调、凸凹和极限等性质， 并通过导数知识，介绍函数的主要性质及图像示意图画法步骤。
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8.函数y=log2(-2x+3)的图像示意图：介绍函数的定义域、单调性、凸凹性、极限等性质，列举函数的五点图表，简要画出函数的示意图。
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9.函数y=e^x(3x+4)的图像示意图：本文通过函数的定义、单调、凸凹性和极限等性质，介绍函数的主要性质及图像画法步骤。
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10.函数y=2^4x的图像示意图：介绍函数的定义域、单调性、凸凹性、极限等性质，列举函数的五点图表，进一步画出函数的示意图。
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田乔灵2287二次函数y=2x^2的图像是抛物线,若抛物线不动X,Y轴向上,向右移2格,解析式为?? -
时张垄15676719244 ______ y轴向上移动2格,相当于y=2x²的图像沿y轴向下平移2个单位,即y+2=2x², y轴向右移动2格,相当于图像沿x轴向左平移2个单位,即y+2=2(x+2)², 因此,最后解析式为:y+2=2(x+2)²,即y=2x²+8x+6
田乔灵22872.一次函数y - 2x+5的图像与x轴交点坐标是() -
时张垄15676719244 ______ 一次函数y=2x+5的图像与x轴交点坐标是(-5/2,0)
田乔灵2287已知y=f(x)是定义在r上的增函数.函数y=f(x+1)的图像关于点( - 1,0)对称,则当f(x^2 - 6x+21)+f(y^2 - 8y) -
时张垄15676719244 ______ 函数y=f(x+1)的图像关于点(-1,0)对称,则说明函数y=f(x)的图像关于原点对称,即f(x)=-f(-x).f(x^2-6x+21)+f(y^2-8y) 又由于y=f(x)是定义在r上的增函数,则有:x^2-6x+21 即:x^2-6x+21+y^2-8y (x-3)^2+(y-4)^2(1)式为关于x,y的方程,表示一个圆心位于(3,4)半径为2的圆域.x^2+y^2表示此圆域内的点到原点的距离,即为圆心到原点(=5)的距离再加或减半径(=2)就OK了,所以最后答案为: (3,7)
田乔灵2287一次函数y=2x - 1的图像与x轴的交点坐标是?与y轴的交点坐标是? -
时张垄15676719244 ______ 当y=0,0=2x-1 x=0.5 一次函数y=2x-1的图像与x轴的交点坐标是(0.5,0) 当x=0 y=2*0-1=-1 与y轴的交点坐标是(0,-1)
田乔灵2287已知一次函数y=2x+1的图像过A(a, - 2)二次函数y=x平方 - (m+1)的图像顶点为D -
时张垄15676719244 ______ 解:1. 要证明二次函数与x轴一定有交点,可转化为证明 方程x^2 -(m+1)x+m =0 有实根.二次方程有实根的充要条件为 △≥0 因 △=b^2 -4ac =[-(m+1)]^2-4*1*m = (m-1)^2 ≥0 所以此二次函数的图像与X轴一定有交点.证毕.2. 由一次函数y=2x+1的图...
田乔灵2287若二次函数Y=X^2+(M+1)X+M的图像关于原点对称后,得到新的函数解析式为y= - x^2 - 2x+1,求原来的函数解析式 -
时张垄15676719244 ______ 你好你的题目有问题应该是二次函数Y=X^2+(M-1)X+M的图像 解由二次函数Y=X^2+(M-1)X+M的图像与函数解析式为y=-x^2-2x+1的图像关于原点对称 取二次函数Y=X^2+(M-1)X+M的图像的点(0,M) 其关于原点的对称点为(0.-M) 即点(0.-M)在y=-x^2-2x+1的图像上 即-M=-0^2-2*0+1 解得M=-1,把M=-1代入二次函数Y=X^2+(M-1)X+M 即原来的函数解析式为y=x²+(-1-1)x+(-1)=x²-2x-1
田乔灵2287函数y=(3 - x)/(1+2x)的图像 -
时张垄15676719244 ______ 首先画出 x=-1/2 再画出y=-1/2 不难看出,这两条线将直角坐标系分为4部分 函数图像是一三象限中的双曲线,但是通过平移,以你画的两条线为渐近线了 但是本质还是反比例函数 不明白找我
田乔灵2287函数 y= f(x+2)与 反函数 f(x+2)的图像 关于什么对对称 -
时张垄15676719244 ______ 法一:设t=x+2,则f(x+2)=f(t),f *(x+2)=f*(t),(注:f*表示反函数)易知,y=f(t)与y=f*(t)的图象关于直线y=t对称,∴y=f(x+2)与y=f*(x+2)的图象关于直线y=...
田乔灵2287已知函数y=mx2+(m2 - m)x+2的图象关于y轴对称,则m=------ -
时张垄15676719244 ______ 因为图象关于y轴对称,所以x=-=0,m≠0,即-=-=0,解得m=1. 当m=0时,此时函数为y=2,这个函数也关于y轴对称,故答案为1或0.
田乔灵2287函数y=1 - 2x除以x+2的图像关于什么对称? -
时张垄15676719244 ______ 解由y=(1-2x)/(x+2)=[1-2(x+2)+4]/(x+2)=[-2(x+2)+5]/(x+2)=-2+5/(x+2) 知函数的对称中心为(-2,-2).故函数y=1-2x除以x+2的图像关于点(-2,-2)对称