物理作为一门理科科目，一直都是学生们学习的难点。今天给大家分享一些关于高中物理实验的动图，希望有助于大家的理解。

直线运动

打点计时器测速度

用DIS测定瞬时速度

自由落体

追及问题—匀加速追匀速

追及问题—匀减速追匀速

真空玻璃管物体的运动

力和力的平衡

不规则物体的重心

演示玻璃瓶的微小形变

演示桌面的微小形变

探究胡克定律

探究力的平行四边形法则

用DIS研究力的分解

牛顿运动定律

力的作用是相互的

用DIS研究牛顿第三定律

验证牛顿第二定律

弹簧测力计演示超重与失重

传送带模型相对位移

动能定理

探究功与速度的关系

动量问题

人船模型

探究碰撞中的不变量

恒定电流

研究路端电压

探究欧姆定律

探究电阻的伏安特性曲线

探究小灯泡伏安特性曲线

用DIS研究小灯泡U-I图像

用DIS测电源电动势和内阻

多用电表测电池内阻

伏安法测电阻分压接法

灵敏电流计改装成电流表

灵敏电流计改装成电压表

半偏法测量电流表内阻

半偏法测量电压表内阻

静电场

感应起电的本质

验证库仑定律

静电屏蔽

等量同种点电荷的电场线

等量异种点电荷的电场线

测量等势线

探究电容大小的影响因素

磁场

分子电流假说

回旋加速器的原理

地磁场

条形磁体的磁场

蹄形磁体的磁场

带电粒子在磁场中的运动

带电粒子在电磁场中的运动

机械波

波发生明显衍射的条件

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晁柱俗2535弹簧测力计,如下图所示,一只弹簧测力计放在光滑的水平面上,弹簧测力计外壳质量不能忽略,弹簧及挂钩质量不计,现对弹簧测力计施加水平方向的力F1... -
鱼炎聪19513091763 ______[答案] 你把F1看成两个力(F1-F2)和F2,所以整个系统可以看做一左一右都是F2的力在拉弹簧,此时弹簧处于平衡状态,读数为F2,可以看成是个平衡系统的内力.而(F1-F2)作用在这个平衡的系统上,提供了向左的加速度. 简化的思路,当F2减小到0...

晁柱俗2535悬挂在铁架台上的弹簧测力计如下图所示.(1)这个弹簧秤的量程是______,分度值是______.(2)图中的字母“N”表示弹簧测力计使用的力的单位是___... -
鱼炎聪19513091763 ______[答案] 由图可知,(1)弹簧秤的量程是0~5N,分度值是0.2N; (2)弹簧测力上的字母“N”表示弹簧测力计使用的力的单位是牛顿; (3)测力前指针与零刻度线没有对齐,需要校零; (4)在实际测量时要使弹簧测力计内的弹簧轴线方向跟拉力方向在一条...

晁柱俗2535图中弹簧测力计最小分度值是______N,图中示数是______N. -
鱼炎聪19513091763 ______[答案] 图中弹簧测力计一个大格表示1N,里面有5个小格,一个小格表示0.2N,其分度值为0.2N.故弹簧测力计的示数=4N+0.6N=4.6N. 故答案为:0.2;4.6.

晁柱俗2535 读出图中弹簧测力计的示数______. -
鱼炎聪19513091763 ______[答案] 由图可知,该弹簧测力计的分度值是0.2N,指针所在位置是3.2N. 故答案是:3.2N

晁柱俗2535观察图中的弹簧测力计,回答下列问题:(1)弹簧测力计是根据______原理制成的;如图弹簧测力计的量程和分度值分别是______、______;图中的弹簧... -
鱼炎聪19513091763 ______[答案] (1)弹簧测力计是根据在弹性限度内,弹簧的伸长量跟它所受的拉力成正比的原理制成的;如图弹簧测力计的量程和分度值分别是0~5N、0.2N;图中的弹簧测力计在使用前,首先要调零. (2)弹簧测力计未悬挂物体时,指针对的刻度是0.4N,如果不...

晁柱俗2535如下图所示,一只弹簧测力计放在光滑的水平面上,弹簧测力计外壳质量不能忽略,弹簧及挂钩质?B -
鱼炎聪19513091763 ______ 选A 因为合力向左,所以向左运动 又因为弹簧受的拉力为两个力中较小的一个(两个力先平衡,额外力再提供加速度),即F2

晁柱俗2535图中的弹簧测力计的示数是______. -
鱼炎聪19513091763 ______[答案] 由图可知,该弹簧测力计的分度值是0.2N,指针所在位置是3.6N. 故答案是:3.6N

晁柱俗2535图中弹簧测力计的示数为 - -----N -
鱼炎聪19513091763 ______ 由图知:弹簧测力计上1N之间有5个小格,所以一个小格代表0.2N,即此弹簧测力计的分度值为0.2N.此时指针指在“1.4”处,所以弹簧测力计示数为1.4N.故答案为:1.4.

晁柱俗2535如图所示弹簧测力计的量程是 - -----N,它的分度值是------N,经过调零后测量,从图中指针位置可知它受到向 -
鱼炎聪19513091763 ______ 如图所示弹簧测力计的量程是0-5N,它的分度值是0.2N,经过调零后测量,从图中指针位置可知它受到向下的拉力是2N.重力的大小可以用弹簧测力计来测量,把物体挂在竖直放置的弹簧测力计的挂钩上,当物体静止时,物体受到的重力就等于弹簧测力计的示数.故答案为:0-5N;0.2;2;弹簧测力计;静止.

晁柱俗2535如图所示弹簧测力计的量程是______N,它的分度值是______N,经过调零后测量,从图中指针位置可知它受到向下的拉力是______N. -
鱼炎聪19513091763 ______[答案] 由图可知,弹簧测力计的量程是0~4N;0~1N之间分成了5等份,因此分度值是0.2N;指针指在1N下面第3个小格上,因此拉力是1N+3*0.2N=1.6N. 故答案为:0~4N、0.2N、1.6N.