11-32+12.4-48轮胎规格

蓝郑林8814,11,32,95,284……n观察寻找规律 -
殳马功15324129527 ______ 851,11-4=732-11=7*395-32=7*3*3284-95=7*3*3*3851-284=7*3*3*3*3...

蓝郑林881解一元一次不等式12 - 4(3X - 1)小于等于2(2X - 16) -
殳马功15324129527 ______ 解:去括号得:12-12x+4≤4x-32 移项得-12x-4x≤-32-12-4 合并同类项得:-16x≤-48 ∴不等式的解集为:x≥3

蓝郑林881已知1=11 - 10+0 2=22 - 21+1 3=33 - 32+2 4=44 - 43+3 .已知1=11 - 10+02=22 - 21+13=33 - 32+24=44 - 43+3.则9=? -
殳马功15324129527 ______[答案] 9=99-98+8

蓝郑林881( - 10) - (+12)+11 - 32 - ( - 24) -
殳马功15324129527 ______ (-10)-(+12)+11-32-(-24) =-10-12+11-32+24 =1

蓝郑林881用一些棋子排成一个每边12个的中空方阵,共四层,求总棋子数 -
殳马功15324129527 ______ 12^2-(12-4)^2=12*12-8*8=144-64=80

蓝郑林8818 - 16= 0 - ( - 30)= 21 - (+32)=()+( - 8)= - 12( - 20) - ( - 4)=( - 4) - ( - 4)=( - 8) - 5=(+6)+()= - 2010 - 18=( - 14) - ( - 26)=( - 4.3) - 6.7=2.5 - ( - 3.5)=( - 2/3) - 1/2=( - 3/4) - ( - 1/3)= -
殳马功15324129527 ______[答案] (-4)+(-8)=-12 (-20)-(-4)=-16 (-4)-(-4)=0 (-8)-5=-3 (+6)+(-26)=-20 10-18=-8 (-14)-(-26)=12 (-4.3)-6.7=-11 2.5-(-3.5)=6 (-3/4)-(-1/3)=-5/12 0))

蓝郑林881 - 32又25分之16/( - 8*4)+(2分之1+3分之2 - 4分之3 - 12分之11)*24, -
殳马功15324129527 ______[答案] -32又25分之16/(-8*4)+(2分之1+3分之2-4分之3-12分之11)*24 =(32+16/25)÷32+1/2x24+2/3x24-3/4x24-11/12x24 =32÷32+16/25÷32+12+16-18-22 =1+1/50-12 =10又49/50

蓝郑林881计算:(1)(+17)+( - 32)+( - 16)+(+24)+( - 1);(2)(+6 )+( - 5 )+(+4 )+( - 1 -
殳马功15324129527 ______ 解:(1)原式=(+17)+(+24)+(-32)+(-16)+(-1)=(+41)+(-49)=-8;(2)原式=(+6 )+(+4 )+(-5 )+(-1 )=11-7=4.

蓝郑林881(12)+(+3)= (+15)+( - 4)= ( - 16)+( - 8)= (+23)+(+24)= ( - 102)+132= ( - 32)+( - 11)= -
殳马功15324129527 ______ (12)+(+3)=12+3=15 (+15)+(-4)=15-4=11 (-16)+(-8)=-16-8=-21 (+23)+(+24)=23+24=47 (-102)+132=-102+132=30 (-32)+(-11)=-32-11=-43 (-35)+0= -35+0=-3578+(-85)=78-85=-7