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(x+1)(x-1)

来源:baiyundou.net   日期:2024-08-24

邢肩览4388求y=2 - ln(x+1)的反函数 -
卞软陶13941028006 ______[答案] y=2-ln(x+1) 2-y=ln(x+1), e^(2-y)=x+1, x=e^(2-y)-1 y=e^(2-x)-1

邢肩览4388因式分解(x+1)的平方乘(x+2) - (x+1)乘(x+2)的平方 -
卞软陶13941028006 ______[答案] (x+1)^2(x+2)- (x+1)(x+2)^2= (x+1)(x+2)(x+1-x-2)=- (x+1)(x+2)=-x^2-3x-2

邢肩览4388y=x/x+1的导数值是多少啊如题 -
卞软陶13941028006 ______[答案] y=x/(x+1) y'=[x'*(x+1)-x*(x+1)']/[(x+1)^2] =[(x+1)-x]/[(x+1)^2] =1/[(x+1)^2] 希望帮你解决了本题.学习顺利.

邢肩览4388函数f(x)的定义域是[0,1],则函数f(x+1)的定义域是 -
卞软陶13941028006 ______[答案] f(x)的定义域是[0,1] 即括号范围是[0,1] ∴x+1范围是[0,1] ∴x∈[-1,0] 定义域是[-1,0]

邢肩览4388ln(根号下(x^2+1))怎么求导 -
卞软陶13941028006 ______[答案] 即f(x)=1/2*ln(x²+1) 所以f'(x)=1/2*1/(x²+1)*(x²+1)' =1/2*1/(x²+1)*2x =x/(x²+1)

邢肩览4388lim x→∞ (x+1/x - 1)∧x+1 求极限 -
卞软陶13941028006 ______ lim(x→∞)[(x+1)/(x-1)]^x=lim(x→∞){[1+2/(x-1)]^[(x-1)/2]}^2*[1+2/(x-1)]=lim(t→∞)(1+1/t)^2t,其中t=(x-1)/2=e^2

邢肩览4388limx趋向无穷 [(X - 1)/(X+1)】^x -
卞软陶13941028006 ______ e的负二次方 原式=limx趋向无穷(1-2/(X+1)) ^(-2/(X+1))·(-(X+1)/2)·X =limx趋向无穷e^(-(X+1)/2)·X =e^-2

邢肩览4388lim[(x+1)/(x - 1)]的x次方怎么求解 -
卞软陶13941028006 ______ ^limx趋近于百无穷大[(x+1)/(x-1)]^x=limx趋近于无穷度大[1+2/(x-1)]^x=limx趋近于无穷回大{1+1/[(x-1)/2]}^x =lim[(x-1)/2]趋近于无答穷大{1+1/[(x-1)/2]}^x=lim[(x-1)/2]趋近于无穷大{1+1/[(x-1)/2]}^[(x-1)+1] =lim[(x-1)/2]趋近于无穷大{1+1/[(x-1)/2]}{1+1/...

邢肩览4388解不等式│(x+1)/(x - 1)│≥1. -
卞软陶13941028006 ______[答案] ∵(题目抄下来) ∴(x+1)/(x-1)≥1或(x+1)/(x-1)≤-1 a 当x>1时,x-1>0 ∴x+1≥x-1或x+1≤1-x ∴1≥-1或x≤0 ∴x>1时不等式成立 b 当x

邢肩览4388⒈已知f(x+2)=x²+2x+1.求f(x) ⒉已知f(x)=x²+x+1.求f(x - 1) 求解 -
卞软陶13941028006 ______ 1、f(x+2)=(x²+4x+4)-2x-4+1 =(x+2)²-2(x+2)+1 ∴f(x)=x²-2x+1 2、f(x-1)=(x-1)²+(x-1)+1 =x²-2x+1+x-1+1 =x²-x+1

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