∫x分之2dx

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∫x分之2dx

来源：baiyundou.net 日期：2024-09-23

IT之家 8 月 14 日消息，今年初，手机 QQ 迎来安装包体积暴增，究其原因是内置了虚幻引擎 4，引发网友热议。

据IT之家小伙伴发现的线索，QQ 音乐 App 在近日的 11.8.09 版本同样迎来体积大增，查看发现 App 中多了一个 28.62MB 的 Cocos2d-x 游戏引擎库。

IT之家了解到，Cocos2d-x 游戏引擎是国内雅基软件开发的游戏引擎，常用于 2D 小型游戏项目开发，支持跨平台。

而 QQ 音乐近日新增了一个名为“Music Zone”的虚拟社区，类似超级 QQ 秀中的“QQ 小窝”，用户可化身虚拟人与其他用户进行社交。

用户可在“Music Zone”中获得一个独立的“家”，并且可以装修自己的“家”，还能把虚拟播放界面和歌单挂在墙上，自己和其他用户都可以进行点播。

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辛阀潘5080高数定积分求∫x^2dx/(x^2+1)]的解. -
敖古奇19634298655 ______[答案] 解 ∫x²dx/(x²+1) =∫[(x²+1)-1]/(x²+1)dx =∫[1-1/(x²+1)]dx =x-acrtanx+C

辛阀潘5080求不定积分x乘cos2分之x 谢谢 -
敖古奇19634298655 ______ ∫xcosx/2dx =2∫xdsinx/2 =2xsinx/2-2∫sinx/2dx =2xsinx/2+4cosx/2+c

辛阀潘5080求不定积分∫2xe^x^2dx -
敖古奇19634298655 ______[答案] ∫2xe^x^2dx =∫e^x^2dx^2 =∫de^x^2 =e^x^2+C

辛阀潘5080∫x(sinx)^2 dx 怎么解? -
敖古奇19634298655 ______ ∫x(sinx)^2dx=∫x(1-cos2x)/2dx=x^2/4-xsin2x/4+∫sin2x/4dx=x^2/4-xsin2x/4-cos2x/8+C分部后尽量使积分号后只剩下代数函数或三角函数而整数次幂函数有有限...

辛阀潘5080∫xcosx/(sinx)^2dx分部积分法咋做? -
敖古奇19634298655 ______[答案] ∫xcosx/sin²xdx=∫xcosx·csc²xdx=-∫xcosxdcotx=-xcosx·cotx+∫cotxdxcosx=-xcosx·cotx+∫[cotx·﹙-xsinx+cosx﹚]dx=-xcosx·cotx+∫﹙-cosx·x+cos²x/sinx﹚dx=-xcosx·cotx-∫cosx·xdx+∫1-s...

辛阀潘5080求定积分∫x/(sinx)^2dx上限为3/π下限为4/π,要过程,最好详细,谢谢! -
敖古奇19634298655 ______ 解:遇到三角函数考虑万能公式.∫x/(sinx)^2dx=∫x/[(1-cos2x)/2]dx=∫2x/(1-cos2x)dx=∫2x/[1-(1-tgxtgx)/(1+tgxtgx)]dx=∫2x(1+tgxtgx)/(2tgxtgx)dx=∫[x/(tgxtgx)]d(tgx) (tgx)'=(1+tgxtgx)=-x/tgx +∫(1/tgx)dx =-x/tgx +lnsinx +C [π/4,π/3]代入:原式=-π/(3sqr3)+0.5(ln3-3ln2)+π/4 ( sqrA是根号A)

辛阀潘5080不定积分∫(X+1)^2dx=? -
敖古奇19634298655 ______[答案] ∫(X+1)^2dx =∫(x+1)^2d(x+1) =(x+1)^3/3+C

辛阀潘5080求∫lnx/x^2dx的不定积分 -
敖古奇19634298655 ______[答案] ∫lnx/x^2dx =-∫lnxd(1/x) =-lnx/x+∫(1/x)dlnx =-lnx/x+∫1/x² dx =-lnx/x-1/x+C

辛阀潘5080求不定积分∫(x^2 - 9)^1/2/xdx(就是X分之根号下x的平方减9的不定积分),∫1/1+(2x)^1/2dx(就是1+根号2x分之一的不定积分),∫1/1+(1 - x^2)^1/2dx(就是1... -
敖古奇19634298655 ______[答案] ∫(x^2-9)^1/2/xdx:用变量替换x=sect,可化为∫(tant)^2dt,然后(tant)^2=(sect)^2-1. ∫1/1+(2x)^1/2dx:用变量替换t=(2x)^1/2,可化为∫t/(1+t)dt,然后分子加1减1进行分项. ∫1/1+(1-x^2)^1/2dx:用变量替换x=sint,可化为∫cost/(1+cost)dt,然后分子...

辛阀潘5080∫x√2x - x^2dx -
敖古奇19634298655 ______[答案] ∫x√2x-x^2dx =√2∫x^(3/2)dx-∫x^2dx =√2*2/5*x^(5/2)-1/3*x^3+C

（编辑：自媒体）