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i+can+t+stand造句

来源:baiyundou.net   日期:2024-09-21

符满刻3280I+can+type+this+letter+for+you改为肯定句答案 -
翟洋生15832549942 ______ I can type this letter for you.我可以帮你打印好这封信.这句就是肯定句,若改为否定句:I can't type this letter for you. 或者改为疑问然后回答肯定句: --Can you type this letter for me?--Yes ,I can. (或者 I can type this letter for you. ) 希望我的回答对您有所帮助,春节快乐,万事如意!

符满刻3280as +adj+n+as与n+as+adj+as的用法如I can't buy as good a book as that one.或者 I can't buy a book as good as that one都可以,但为什么“as good books as... -
翟洋生15832549942 ______[答案] 只要记住一点就明白了:as 必须且只能用来修饰形容词,如果as被用来修饰一个名词,肯定就错了.I can't buy as good a book as that one.这句正确,因为as是和good一起用的,非用来修饰名词book,因为有一个a阻止了as和boo...

符满刻3280C语言 请编写 1+3+6+10+15+...+n = ? 输入n 然后能输出这个数列的和,怎么编写代码? -
翟洋生15832549942 ______ main() { int i,n,t=0; long s=0; scanf("%d",&n); for(i=1;i<=n;i++) { t+=i; s+=t; } printf("%ld",s); }

符满刻3280I+cant++believe+our+trip+is+over.+翻译 -
翟洋生15832549942 ______ I can't believe our trip is over.我不敢相信我们的旅行结束了.

符满刻3280I+can++clane++my++room+.+改为否定句 -
翟洋生15832549942 ______ I can clean my room.我可以打扫我的房间.否定句 :I can't clean my room. I cannot clean my room.我不能打扫我的房间.

符满刻3280C语言求y= n∑r=1,1/r^2+1精度要求为1/r^2+1<1e - 6 -
翟洋生15832549942 ______ #include <stdio.h> void main() { int a[1000]={1},b[4]={0}; int k,i,j; scanf("%d",&k); void multi(int a[],int b[]); // 用于计算乘法的函数,计算a*b 并把结果放在a当中 void seperate(int n, int b[]); //分离一个数的没一位,并放在b中!for (i=1;i<=k;i++) { ...

符满刻3280关于that/so+adj后是否可以不加从句I can't walk - ___far.用"that"or"so"? -
翟洋生15832549942 ______[答案] 此处填so,表示“如此” 你应该是想问so……that的用法吧. so+adj+that+从句 i am so tired that i can't get up. 我如此累以至于不能起床.这种句型,that后一定要跟从句.

符满刻3280用may,can,must,分别用什么回答(肯定,否定语态都要)
翟洋生15832549942 ______ May I...? Yes, you may. No, you mustn't/can't/may not. Can I ...? Yes, you can. No, you can't. Must I...? Yes, you must. No, you needn't. can't 不能,不会 mustn't 禁止,绝对不可以

符满刻3280java的循环语句九九乘法(i+"*"+j+"="+(i*j)+"\t");中的"+j+"什么意思? -
翟洋生15832549942 ______ 这句话应该是输出语句中的,双引号中间的是直接输出的字符串,+表示连接,假设,i=1,j=2输出的为:1*2=2 \t为制表符

符满刻3280质点的运动方程r=(t - 0.5t^2)i+(1+2t+1/3*t^3)j,求t=2秒时加速度和速度? -
翟洋生15832549942 ______[答案] 速度v=dr/dt=(1-t)i+(2+t^2)j=-i+6j 大小是根号下(-1)2+62=根号下37 加速度a=dv/dt=-i+2tj=-i+4j 大小是根号下(-1)2+42=根号下17

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