limx0cotx等于多少

濮砍缪3595求极限 当x趋向于0 (cosx)^cotx -
萧京终18699352295 ______[答案] 1^∞型的公式 lim(x-->x0)f(x)^g(x)是1^∞型 先计算lim(x->x0)g(x)[f(x)-1]=A 那么lim(x-->x0)f(x)^g(x)=e^A (x0可以使任意极限过程) lim(x-->0)cotx*(cosx-1)=lim(x->0)(cosx-1)/sinx=0 所以原极限就是1

濮砍缪3595limx趋近于0lncotx/lnx -
萧京终18699352295 ______[答案] limx趋近于0lncotx/lnx =lim(x->0) 1/cotx ·(-csc方x)/(1/x) =lim(x->0) -x/(sinxcosx) =-lim(x->0) x/(x) =-1

濮砍缪3595lim(x趋向于0+)(cotx)^tanx 答案是1,求助〜lim(x趋向于0+)(cotx)^tanx答案是1,求助〜求详细过程 -
萧京终18699352295 ______[答案] ∵lim(x->0+)[tanx*ln(cotx)]=lim(x->0+)[ln(cotx)/cotx] =lim(t->+∞)(lnt/t) (令t=cotx) =lim(t->+∞)(1/t) (∞/...

濮砍缪3595limx趋向+0时(cotx)^(tan2x) -
萧京终18699352295 ______ = lim(x->0)e^(tan2x ln(cotx)) =e^(lim(x->0)(2tanx/(1-tan^2(X))*(ln(1/tanx)) =e^(lim(x->0)(-2tan^2(x)/1-tan^2(X)) =e^(lim(x->0)(0/1-0) = e^0 = 1

濮砍缪3595问:lim其中x—>0+时求limx^(cotx)=?要有步骤 -
萧京终18699352295 ______ =e^lim cotx·lnx =e^lim (lnx/tanx) =e^lim (lnx/x) =e^lim (1/x) →+∞

濮砍缪3595lim(x趋向于0+)x^tanx 求极限? -
萧京终18699352295 ______[答案] lim(x趋向于0+)x^tanx =e^lim(x趋向于0+)lnx^tanx =e^lim(x趋向于0+)lnx*tanx =e^lim(x趋向于0+)lnx/cotx (∞/∞) =e^lim(x趋向于0+)(1/x)/(-csc^2x) =e^lim(x趋向于0+)-sinx =e^0 =1

濮砍缪3595x趋近0,lim xcotx 为什么不能写成 limx乘lim cosx乘x/lim sinx乘x,就有lim x乘limcosx/x乘limx/sinx -
萧京终18699352295 ______ limcosx/x=1这个极限不存在 所以 不能拆开 书上极限运算法则是在 极限都存在的情况下,才能拆开的.

濮砍缪3595当x趋向0 (cotx - 1/x)的极限 -
萧京终18699352295 ______[答案] 当x趋向0 (cotx-1/x)的极限 =lim(x->0)(cosx/sinx-1/x) =lim(x->0)(xcosx-sinx)/xsinx =lim(x->0)(xcosx-sinx)/x^2 =lim(x->0)(-xsinx)/2x =lim(x->0)(-x^2)/2x =0

濮砍缪3595lim(x→0)(1+1/cotx)^(1/x)=? 书上的答案是e 我不明白怎么得来的 -
萧京终18699352295 ______[答案] x→0,x和tanx是等价无穷小 原式=lim(x→0)(1+tanx)^(1/x =lim(x→0)(1+x)^(1/x) =lim(x→∝)(1+1/x)^x=e 最后一步可在任何一本高等数学书上找到

濮砍缪3595极限x趋近于0,lim(1/(x^2) - cotx)=? -
萧京终18699352295 ______[答案] lim(x->0) 1/(x^2-cotx) =lim(x->0) sinx/(x^2.sinx -cosx) =0