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python输出成绩从大到小

来源:baiyundou.net   日期:2024-09-21

作者:kopykawai

这种架标如果是磁吸的就好了,考虑打报告整几个... 

阅读理由

又双叒叕有人托某馆员借书...Python 编程类书在库里找出几百本倒是毫无难度。但希望适合低年级小朋友学习,最好每章节后还有选择或者填空之类的习题就不太好整了,某馆员干脆牙一咬心一横找了本中学教材。为了保险自己还是照例先读审一遍吧... 

简单总结&读后感

大概翻了一下感觉本书算是那种非常正统的“课本”,换句话说大概就是基本没有“激发读者阅读兴趣”这方面的考虑...反正只要学生按部就班的一路学下去就总能有所收获,起码编个排序或者小游戏之类的程序大概没有问题... 

推荐需要这方面课程内容参考的教育工作者整一本读读... 

晒书

看见这封面某馆员不由不感叹最近几年课本内容质量不好说,起码封面是越来越好看了... 

不过这个价格是真心有点承受不起... 

百度了一下北京八中,百年名校...北方某小城市的教育质量不是我们这华中小县城能比的... 

大凡是个学校总要选一些优秀教师拍几张这样的照片的...看看职称都比某馆员高... 

想了想这书也算自编教材吧,出现学校的照片非常合理... 

一打开依然是某馆员读了几十年的课本的熟悉味道...其实大部分课本的排版都挺优秀的... 

国内课本里的卡通形象设计是稍微差点火候... 

看见课后习题顿时回到了那只需要担心考试成绩的年少时光... 

Thonny这个名字挺好听的。 

书中表格不少,这样的排版看着就有点迷糊... 

编程什么的当然还是要靠实践,所以还是装个 Thonny 耍耍看... 

故意打错一个符号,错误提示非常清楚明白... 

程序成功运行了! 

阅读更多科学技术精彩内容,可前往什么值得买查看

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须凤吉4671写一个python脚本 -
司肤袁13674568444 ______ #!/usr/bin/env python import sys str = True while (str): dig = int(input()) if dig > 100: print 'please input mun between 0~100' elif dig >= 90: print 'A' elif dig >= 80: print 'B' elif dig >= 70: print 'C' elif dig >= 60: print 'D' elif dig print 'E' else: break

须凤吉4671如下python代码中t[1]为什么就取到成绩 -
司肤袁13674568444 ______ by_score作为sorted的排序函数使用时,它接受的是L的每一个元.因此,t即列表L中的一个元组('Bob',75)这样的.而在Python中,元组与列表的序号都是从0开始的,t[1]即为该元组第二个元素,即75.这就是成绩.只使用一次的话可以这样写:L2 = sorted(L, key = lambda x:x[1],reverse=True)

须凤吉4671下列 Python语句的程序运行结果为 list1=[1,2,3];list2=[3,4,5];dict1=...
司肤袁13674568444 ______ python用缩进控制语句结构,第一个输出语句其实是与if结构同级,第二个输出与else中for结构同级,第三个输出语句属于else中的for结构中.三个输出在不同的结构块中,所以输出不同

须凤吉4671在主函数中输入N个学生3门功课的成绩.用另一函数对它们进行按总成绩从大到小的顺序进行排序. -
司肤袁13674568444 ______ #include using namespace std;#define N 50 void sort(int(*str)[4]) { int i,j; int p; for(i=0;i for(j=i;j if(str[i][3] { p=str[i][0]; str[i][0]=str[j][0]; str[j][0]=p; p=str[i][1]; str[i][1]=str[j][1]; str[j][1]=p; p=str[i][2]; str[i][2]=str[j][2]; str[j][2]=p; p=str[i][3]; str[i][3]=str[j][3]; str[j][3]=p...

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