sin50度+1+根号3tan10度

司菡枝4596求值:Sin50度(1+根号3乘以tan10度)请写出化简的过程等 -
骆洪弘18943695766 ______[答案] Sin50度(1+根号3乘以tan10度) =sin50°(1+tan60°tan10°) =sin50°*(cos60°con10°+sin60°sin10°)/cos60°cos10° =sin50°*cos(60°-10°)/cos60°cos10° =sin100°/2cos60°cos10° =cos10°/cos10° =1 这里tan60°=√3,cos60°=1/2,sin100°=cos10°

司菡枝4596sin50°(1+根号3tan10°)等于多少 -
骆洪弘18943695766 ______[答案] sin50(1+√3tan10) =sin50[1+√3(sin10/cos10)] =sin50[(cos10+√3sin10)/cos10] =sin50[2sin(30+10)/cos10] =(2sin50sin40)/cos10° =(2cos40°*sin40°)/cos10° =sin80°/cos10° =cos10°/cos10° =1

司菡枝4596利用三角函数公式化简 sin50度(1+根号3 tan10度) -
骆洪弘18943695766 ______[答案] sin50(1+√3 tan10) =sin50(tan60-tan10)/tan(60-10) =sin50/tan50*(sin60/cos60-sin10/cos10) =cos50*(sin60cos10-sin10cos60)/(cos60cos10) =cos50*sin(60-10)/(cos60cos10) =1/2sin100/(cos60cos10) =sin80/cos10 =1

司菡枝4596化简:sin50度(1+根号3*tan10度) -
骆洪弘18943695766 ______ sin50(1+√3tan10)=sin50(cos10+√3sin10)/cos10=sin50*2sin(10+30)/cos10=2sin50sin40/cos10=2sin50cos50/cos10=sin100/cos10=sin80/cos10=cos10/cos10=1

司菡枝4596sin50度(1+根号3tan10度) -
骆洪弘18943695766 ______[答案] 第一步sin50*(1+3^0,5*tan10)=sin50*((tan60-tan10)/tan50).利用tan(60-10)=tan60-tan10/1+tan60*tan10 第二步:化简得cos50*(tan60-tan10)=cos50*(cos10*3^0.5-sin10)/cos10=(3^0.5*cos50-cos50*sin10)/cos10 第三步:这儿方法有很多,我只写一...

司菡枝4596化简 三角函数sin50°[1+(根号3)*(tan10°)] -
骆洪弘18943695766 ______[答案] sin50°[1+(√3)*tan10°] =sin50*[(√3)sin10+cos10]/cos10 =(sin50/cos10)*2*(cos30sin10+cos10sin30) =(sin50/cos10)*2*sin40 =2*sin50*cos50/cos10 =sin100/cos10 =cos10/cos10 =1

司菡枝4596sin50度(1+根号3(tan10度)) -
骆洪弘18943695766 ______[答案] sin50度(1+根号3(tan10度)) =2*sin50度(1/2*cos10度+(根号3)/2*sin10度)/cos10度 =2*sin50度(cos60度*cos10度+sin60度*sin10度)/cos10度 =2*sin50度cos50度/cos10度 =sin100度/cos10度 =1...

司菡枝4596sin50°(1+(根号3)tan10°)= -
骆洪弘18943695766 ______[答案] 原式=sin50(1+√3sin10/cos10) =(sin50/cos10)*(cos10+√3sin10) =(sin50/cos10)*2sin(10+z) 其中tanz=1/√3 所以z=30度 所以原式=(sin50/cos10)*2sin(10+30) =2(cos40/cos10)*sin40 =sin80/sin80 =1

司菡枝4596化简sin50度(1 根3tan10度) -
骆洪弘18943695766 ______[答案] sin50°*(1+根号3*tan10°) =sin50°*(1+根号3*sin10°/cos10°) =sin50°/cos10°*(cos10°+根号3*sin10°) =2*sin50°/cos10°*(1/2*cos10°+根号 3/2*sin10°) =2*sin50°/cos10°*(sin30°*cos10° +cos30°*sin10°) =(2*sin50°/cos10°)* sin40° =(2*cos40°/cos10...

司菡枝4596sin50(1+根号3乘以tan10) -
骆洪弘18943695766 ______[答案] sin50(1+根号3乘以tan10)=sin50*(1+根号3*sin10/cos10) =sin50*(cos10+根号3*sin10)/sin10 =sin50*2*(1/2*cos10+根号3/2*sin10)/cos10 =sin50*2...