cosx+sinx怎么化简

贝购容893cosx+sinx化成余弦函数的形式.
家易俘19865287603 ______ acosx+bsinx= 根号(a²+b²)*sin(x+φ).tanφ=a/b. cosx+sinx=根号2sin(x+π/4).

贝购容893函数f(x)=cosx+sinx/cosx - sinx,如何化简成f(x)=A sin(ωx+φ)的形式? -
家易俘19865287603 ______[答案] f(x)=(cosx+sinx)/(cosx-sinx) 上下除cosx =(1+tanx)/(1-tanx) =(tanπ/4+tanx)/(1-tanπ/4*tanx) =tan(x+π/4)

贝购容8933sinx+cosx怎样化简成复合函数 -
家易俘19865287603 ______[答案] 3sinx+cosx =√10(3/√10sinx+1/√10cosx) =√10sin(x+t) cost=3/√10 sint=1/√10

贝购容893y=cosx+sinx怎样化为Y=Acoswx+amp;
家易俘19865287603 ______ y=cosx+sinx=(√2)[(√2)/2cosx+(√2)/2sinx]=(√2)[sin(π/4)cosx+cos(π/4)sinx]=(√2)sin[x+(π/4)]其中:A=√2,ω=1,φ=π/4

贝购容893根号3cosX+sinX怎么化简 -
家易俘19865287603 ______ @代表阿尔法 &代表贝塔 asin@+bsin@ =根号(a方+b方)sin(@+&) 其中,sin&=(根号(a方+b方))除以b cos&=(根号(a方+b方))除以a

贝购容893如何将1+sinx+cosx这个式子化成积的形式 -
家易俘19865287603 ______[答案] 1+sinx+cosx =1+cosx+sinx =2[cos(x/2)]^2+2sin(x/2)cos(x/2) =2cos(x/2)[cos(x/2)+sin(x/2)] =2√2cos(x/2)[√2/2*cos(x/2)+√2/2sin(x/2)] =2√2cos(x/2)sin(x/2+π/4)

贝购容893求证:cosx+sinx=根号2cos(x - π/4) -
家易俘19865287603 ______ cosx+sinx =√2[((√2/2)cosx+(√2/2)sinx] =√2[cosxcos(π/4)+sinxsin(π/4)] =√2cos(x-π/4) 得证

贝购容893sinx+cosx==√2sin(x+π/4) ,像这种题目可以化成y= Asin(wx+b),里面的A,w,b是怎么求出来的?A=sinx前面的系数和cosx前面的系数的平方和开根号?w=?b=? -
家易俘19865287603 ______[答案] A=√(1²+1²)=√2(看两个前面的系数) w=1(看x前面的系数) tanb=1/1=1 所以b=π/4(这里b也是看sinx与cosx前面的系数的比值)

贝购容893问:2sinxsinx+√3sinxcosx+cosxcosx怎么化简的求详解 -
家易俘19865287603 ______[答案] 原式 =sin²x+ 2√3sinxcosx+(sin²x+cos²x) =(1-cos2x)/2+√3sin2x+1 =√3sin2x-1/2cos2x+3/2 =sin2xcosπ/6-cos2xsinπ/6+3/2 =sin(2x-π/6)+3/2

贝购容8932sin²x+2sinxcosx怎么化简 -
家易俘19865287603 ______[答案] 2sin²x+2sinxcosx =1-cos2x+sin2x =1+sin2x-cos2x =1+√2sin(2x-π/4)