拱高弦长求弧长计算器
管宜奚1116圆中,弦长6米,拱高2米,求半径及弧长,在线等,谢谢 -
鬱胀连13025614827 ______ 弦长L=6米,拱高H=2米,求半径R及弧长C?R=(L^2+4*H^2)/(8*H) =(6^2+4*2^2)/(8*2) =(36+16)/16 =52/16 =3.25米 圆心角A=2*ARC SIN(L/(2*R)) =2*ARC SIN(6/(2*3.25)) =2*ARC SIN(0.92308) =67.38度 =67.38*PI/180 =1.176弧度 C=A*R =1.176*3.25 =3.822米 半径为3.25米,弧长为3.822米.
管宜奚1116弧弦长ACL=800厘米,拱高BOH=100,求弧长c -
鬱胀连13025614827 ______ 弦长L=800厘米,拱高H=100,求弧长C?弧半径为R,弧所对的圆心角为A.R^2=(R-H)^2+(L/2)^2 R^2=R^2-2*R*H+H^2+L^2/42*R*H=H^2+L^2/4 R=H/2+L^2/(8*H) =100/2+800^2/(8*100) =850厘米 A=2*ARC SIN((L/2)/R) =2*ARC SIN((800/2)/850) =56.145度 C=PI*R*A/180=PI*850*56.145/180=832.9厘米
管宜奚1116已知弦长960CM,拱高120CM 求弧长 -
鬱胀连13025614827 ______ 设半径是R,有 R^2=480^2+(R-120)^2 解得R=540,设圆心角是2k,有 tank=8/7,所以 tan2k=-112/15.所以弧长=540*arctan(-112/15).
管宜奚1116求弦长、弧长拱高的数字公式 -
鬱胀连13025614827 ______[答案] 知道弦长和拱高求弧长,弦长是L=3.28m拱高是H=0.6m,求弧长C多少m?弧半径为R,弧所对的圆心角为A.R^2=(R-H)^2+(L/2)^2R^2=R^2-2*R*H+H^2+L^2/42*R*H=H^2+L^2/4R=H/2+L^2/(8*H) =0.6/2+3.28^2/(8*0.6) =2.5413mA=2*ARC...
管宜奚1116已知弦长2.93米,拱高0.305米,求圆心角和弧长 -
鬱胀连13025614827 ______[答案] 已知弦长L=2.93米,拱高H=0.305米,求圆心角A和弧长C?弧半径为R.R^2=(R-H)^2+(L/2)^2R^2=R^2-2*R*H+H^2+L^2/42*R*H=H^2+L^2/4R=H/2+L^2/(8*H)=0.305/2+2.93^2/(8*0.305)=3.5184米A=2*ARC SIN((L/2)/R)=2*ARC SIN((...
管宜奚1116已知弧长600,拱高80,求弦长及公式 -
鬱胀连13025614827 ______[答案] 已知弧长C=600,拱高H=80,求弦长L及公式?弧半径为R,弧所对的圆角为A.Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*RnR0=562R1=547.98R2=548.621R3=548.623R4=548.623R=548.623A=C/R=600/548.623=1.0936...
管宜奚1116已知圆弧弦长25米,拱高1.5米,求弧长? -
鬱胀连13025614827 ______[答案] 已知圆弧弦长L=25米,拱高H=1.5米,求弧长C?弧半径为R,弧所对的圆心角为A.R^2=(R-H)^2+(L/2)^2R^2=R^2-2*H*R+H^2+L^2/42*H*R=H^2+L^2/4R=H/2+L^2/(8*H) =1.5/2+25^2/(8*1.5) =52.833米A=2*ARC SIN((L/2)/R =2*ARC S...
管宜奚1116己知弦长及拱高怎样求弧长 -
鬱胀连13025614827 ______[答案] 己知弦长L及拱高H怎样求弧长C? 弧半径为R,弧所对的圆心角为A. R^2=(R-H)^2+(L/2)^2 R^2=R^2-2*R*H+H^2+L^2/4 2*R*H=H^2+L^2/4 R=H/2+L^2/(8*H) A=2*ARC SIN((L/2)/R) C=π*R*A/180
管宜奚1116已知玄长、拱高、半径,求弧长 -
鬱胀连13025614827 ______[答案] 已知弦长L,拱高H,求半径R? R=H/2+L^2/(8*H) 已知弧长C,弦长L,求半径R? Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn 给一个合适的初始值R0,求得R. 已知弧长C,拱高H,求半径R? Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*...
管宜奚1116知道拱形的弦长为3490cm拱高为475cm如何求出弧长是多少 急用!感谢 -
鬱胀连13025614827 ______[答案] 知道拱形的弦长为L=3490cm拱高为H=475cm如何求出弧长C是多少?弧半径为R,弧所对的圆心角为A.R^2=(R-H)^2+(L/2)^2R^2=R^2-2*R*H+H^2+L^2/42*R*H=H^2+L^2/4R=H/2+L^2/(8*H) =475/2+3490^2/(8*475) =3442.8cmA=2*ARC S...