sin50+1++3tan10

苗定购628sin50度(1+根号3tan10度=? -
盛林菡17268631117 ______ 原式=sin50°*[1+根号3(sin10°/cos10°)]=sin50°*[(cos10°+根号3sin10°)/cos10°]=sin50°*[2sin(30°+10°)/cos10°]=(2sin50°*sin40°)/cos10°=(2cos40°*sin40°)/cos10°=sin80°/cos10°=cos10°/cos10°=1

苗定购628求值:sin50度(1+根号3tan1o度) -
盛林菡17268631117 ______ =sin50(1+tan60tan10) =sin50(tan60-tan10)/tan(60-10) =cos50(tan60-tan10) =cos50(sin60cos10-sin10cos60)/cos60cos10 =cos50sin50/cos60cos10 =cos10/(2*1/2*cos10) =cos10/cos10 =1

苗定购628求值:sin50°(1+√3tan10°) 请给出详细的解题过程,一定采纳! -
盛林菡17268631117 ______ cos10° = sin(180°-80°) / cos10° = sin80°..sin50°(1+根号3tan10°) = sin50°(cos10°+根号3sin10°) / cos10° = sin50° * 2(cos60°cos10°+sin60°sin10°) / cos10° = sin50° * 2 cos(60°-10°) / cos10° = 2 sin50°cos50° / cos10° = sin100° /

苗定购628计算sin50(1+根号3tan10)= -
盛林菡17268631117 ______ 结果为1.先将正切化弦,把分母cos10提到括号外面,然后把括号里面合并得2sin50,最后化简得1

苗定购628计算:sin50°(1+根号3tan10°)=? -
盛林菡17268631117 ______ sin50°*(1+根号3*tan10°) =sin50°*(1+根号3*sin10°/cos10°) =sin50°/cos10°*(cos10°+根号3*sin10°) =2*sin50°/cos10°*(1/2*cos10°+根号 3/2*sin10°) =2*sin50°/cos10°*(sin30°*cos10° +cos30°*sin10°) =(2*sin50°/cos10°)* sin40° =(2*cos40°/cos10°)* sin40° =(2* sin40°cos40°)/ cos10° =sin80°/cos10° =cos10°/cos10° =1

苗定购628sin50度(1+根号3tan10度)解题过程
盛林菡17268631117 ______ sin50°(1+√3tan10°)=2sin50°[1/2+(√3/2)sin10°/cos10°]=2sin50°[1/2cos10°+(√3/2)sin10°]/cos10° =2sin50°[cos60°cos10°+sin60°sin10°]/cos10° =2sin50°cos(60°-10°) /cos10° =2sin50°cos50° /cos10° =sin100°/cos10° =cos10°/cos10°=1

苗定购628高中数学+化简sin50°(1+根号3tan10°) -
盛林菡17268631117 ______[答案] sin50(1+√3tan10)=sin50[1+√3(sin10/cos10)]=sin50[(cos10+√3sin10)/cos10]=sin50[2sin(30+10)/cos10]=(2sin50sin40)/cos10°=(2cos40°*sin40°)/cos10°=sin80°/cos10°=cos10°/cos10°=1

苗定购628求证sin50(度)*(1+根号3tan10(度))=1
盛林菡17268631117 ______ sin50°(1+√3*tan10°) =sin50°(1+tan60°*tan10°) =sin50°(1+sin60°sin10°/cos60°cos10°) =sin50°(sin60°sin10°+cos60°cos10°)/cos60°cos10° =sin50°cos50°/cos60°cos10° =2sin50°cos50°/cos10° =sin100°/cos10° =cos10°/cos10° =1

苗定购628sin50°(1+根号3tan10°)等于多少 -
盛林菡17268631117 ______[答案] sin50(1+√3tan10) =sin50[1+√3(sin10/cos10)] =sin50[(cos10+√3sin10)/cos10] =sin50[2sin(30+10)/cos10] =(2sin50sin40)/cos10° =(2cos40°*sin40°)/cos10° =sin80°/cos10° =cos10°/cos10° =1

苗定购628sin50°(1+根号3tan10°)的值????在线求解!!!!详细过程.看懂就采纳!!! -
盛林菡17268631117 ______ cos40度(1+根号3tan10度)=2(cos40/cos10)((1/2)cos10+((根号3)/2)sin10)=2(cos40/cos10)sin(10+30)=sin80/cos10=1 所以:cos^2 20度分之sin50度+cos40度(1+根号3tan10度)=(1+sin50)/(cos20)^2=(1+sin50)/((1+cos40)/2)=2(1+sin50)/(1+cos40)=2(1+cos40)/(1+cos40)=2