tan+x-y+三角函数公式

邢家瞿1537三角函数(请写出过程)求证:tan(x - y)+tan(y - z)+tan(z - x)=tan(x - y)tan(y - z)tan(z - x) -
衡朋钞19815518171 ______[答案] 两角和正切公式: tan[(x-y)+(y-z)]=[tan(x-y)+tan(y-z)]/[1-tan(x-y)tan(y-z)] tan(x-y)+tan(y-z) =tan(x-y+y-z)*[1-tan(x-y)tan(y-z)] =tan(x-z)*[1-tan(x-y)tan(y-z)] =tan(x-z)-tan(x-z)tan(x-y)tan(y-z) =-tan(z-x)+tan(z-x)tan(x-y)tan(y-z) 所以tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)...

邢家瞿1537【高一数学、一道简单的三角函数】已知tanX=3/2,tanY=1/2/,求X - - Y=?不一定要求值出来.用其他三角函数表示也可. -
衡朋钞19815518171 ______[答案] tan(X-Y)=(tanX-tanY)/(1+tanXtanY)=(3/2-1/2)/(1+3/2*1/2)=4/5

邢家瞿1537已知sin x +sin y =1/4,cos x +cos y =1/3,则tan (x +y -
衡朋钞19815518171 ______ 解:sinx+siny=2sin[(x+y)/2]cos[(x-y)/2]=1/4 ① cosx+cosy=2cos[(x+y)/2]cos[(x-y)/2]=1/3 ② ①÷②,得 tan[(x+y)/2]=3/4 tan(x+y)=2tan(x+y)/2/1-tan²(x+y)/2=(3/4)/[1-(3/4)²]=24/7

邢家瞿1537三角函数恒等变换 -
衡朋钞19815518171 ______ 三角函数是数学中属于初等函数中的超越函数的一类函数.它们的本质是任意角的集合与一个比值的集合的变量之间的映射.通常的三角函数是在平面直角坐标系中定义的,其定义域为整个实数域.另一种定义是在直角三角形中,但并不完全....

邢家瞿1537三角函数有哪些? -
衡朋钞19815518171 ______ ·两角和与差的三角函数: cos(α+β)=cosα·cosβ-sinα·sinβ cos(α-β)=cosα·cosβ+sinα·sinβ sin(α±β)=sinα·cosβ±cosα·sinβ tan(α+β)=(tanα+tanβ)/: tanα·cotα=1 sinα·cscα=1 cosα·secα=1 三角函数恒等变形公式: sin^2(α)+cos^2(α)=1 tan^...

邢家瞿1537三角函数问题(高一)求证tan(x - y)tan(y - z)tan(z - x)=tan(x - y)+tan(y - z)+tan(z - x)要求过程,思路,不用太复杂,也不用担心我看不懂!解出来我给50分! -
衡朋钞19815518171 ______[答案] tan(x-y) - tan(x-y)tan(y-z)tan(z-x) = tan(x-y) [1-tan(y-z)tan(z-x)] .(b) ∵ tan(y-x) = tan[(y-z) + (z-x)] = tan(y-z)tan(z-x)/ [1- tan(y-z)tan(z-x)] ∴ tan(x-y)[1-tan(y-z)tan(z-x)] = -tan(y-z)tan(z-x) .(a) 将(a)代入(b): ∴tan(x-y) - tan(x-y)tan(y-z)tan(z-x) = -tan(y-z)tan(z-x)...

邢家瞿1537求证:tan(x+y)+tan(x - y)=sin2x/cosx*cosx - siny*siny -
衡朋钞19815518171 ______[答案] tan(x+y)+tan(x-y)=sin(x+y)/cos(x+y)+sin(x-y)/cos(x-y)=[sin(x+y)cos(x-y)+cos(x+y)sin(x-y)]/[cos(x+y)cos(x-y)]=sin2x/[(cosxcosy-sinxsiny)(cosxcosy+sinxsiny)]=sin2x/[(cosx)^2(cosy)^2-(sinx)^2(siny)^2]=si...

邢家瞿1537若tan2x=3tan(x - y)=3,则tan(x+y)=______. -
衡朋钞19815518171 ______[答案] ∵tan2x=3tan(x-y)=3, ∴tan2x=3,tan(x-y)=1, 则tan(x+y)=tan[2x-(x-y)]= tan2x−tan(x−y) 1+tan2xtan(x−y)= 3−1 1+3= 1 2. 故答案为: 1 2

邢家瞿1537求下列隐函数的一阶导数y' y=tan(x+y)的导数特别是三角函数几个变换的公式,以及在哪里使用 -
衡朋钞19815518171 ______[答案] y'=sec^2(x+y)*(1+y')y'(1-sec^2(x+y))=sec^2(x+y)y'*tan(x+y)=-sec^2(x+y)y'=-1/cos^2(x+y)*1/tan(x+y)=-1/[sin(x+y)cos(x+y)]=-2/sin(2x+2y)=-2csc(2x+2y)y''=2cot(2x+2y)csc(2x+2y)*(2+2y')把y'代入即可

邢家瞿1537数学 三角函数 变换y=tan(x+y).y`=sec2(x+y)(1+y`).y`=sec2(x+y)/1 - sec2(x+y)= - (y2+1/y2)? 求最后一步详解. -
衡朋钞19815518171 ______[答案] 由公式sec²a=tan²a+1 所以sec²(x+y)=tan²(x+y)+1 而y=tan(x+y). 所以sec²(x+y)=y²+1