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来源:baiyundou.net   日期:2024-08-24

导数五步法画函数图像10个函数示意图应用举例之一

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1.函数y=(12x2+9)(4x2+14)的图像示意图:介绍函数的定义域、单调性、凸凹性、极限等性质及五点图表,并通过导数知识计算函数的单调和凸凹区间,简要画出示意图。

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2.函数y=(19x2+5)√(4x2+9)的主要性质及其图像:介绍函数的定义域、单调性、凸凹性、极限等性质,列举函数的五点图表,进一步画出函数的示意图。

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3.函数y=4√(x+80)^7图像画法及步骤:本文通过函数的定义、单调、凸凹性和极限等性质,介绍函数的主要性质及图像画法步骤。

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4.曲线x³+y³=2的主要性质及其图像示意图:介绍曲线方程的定义域、单调性、凸凹性等性质,同时用导数的知识求解函数的单调区间和凸凹区间,并简洁画出函数的图像示意图。

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5.√(x+4)+√(3y+5)=2的图像示意图:介绍曲线方程的定义域、单调性、凸凹性及极限等性质,同时用导数简洁画出函数的图像示意图。

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6.函数y=16x3+8x的图像示意图及主要性质:介绍函数的定义域、单调性、凸凹性、极限等性质,列举函数的五点图表,进一步画出函数的示意图。

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7.函数y=√(20x-87)^5图像画法及步骤:通过函数的定义、单调、凸凹和极限等性质, 并通过导数知识,介绍函数的主要性质及图像示意图画法步骤。

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8.函数y=log2(-2x+3)的图像示意图:介绍函数的定义域、单调性、凸凹性、极限等性质,列举函数的五点图表,简要画出函数的示意图。

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9.函数y=e^x(3x+4)的图像示意图:本文通过函数的定义、单调、凸凹性和极限等性质,介绍函数的主要性质及图像画法步骤。

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10.函数y=2^4x的图像示意图:介绍函数的定义域、单调性、凸凹性、极限等性质,列举函数的五点图表,进一步画出函数的示意图。

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常乳宽3608函数(x+y - 1) - xy=0的图像
邰言贷18992508708 ______ x-1+y-xy=0 (x-1)-y(x-1)=0 (x-1)(1-y)=0. 很明显图像是x=1或y=1的两条相交直线.

常乳宽3608y=1/x - 2 +x+1(x>2)的图像最低点坐标 -
邰言贷18992508708 ______ y=1/(x-2)+x+1=(x-2)+1/(x-2)+3>=2+3=5,当且仅当x=3时等号成立.所以,y=1/x-2 +x+1(x>2)的图像最低点坐标是(3,5).

常乳宽3608z^2=x^2+y^2的图像? -
邰言贷18992508708 ______ 圆锥面

常乳宽3608x^2+xy+y^2=0 的图象是什么样的? -
邰言贷18992508708 ______[答案] 图象就只有原点 ∵x^2+xy+y^2=0 ∴(x+1/2*y)^2+3/4*y^2=0 在实数范围内只有一x=0,y=0

常乳宽3608将函数y=x方+x的图像向右平移a(a>0)个单位,得到函数y+x方 - 3x+2的图像.则a的值为?求解释! -
邰言贷18992508708 ______ 将函数y=x^2+x的图像向右平移a(a>0)个单位,得到函数y=x^2-3x+2的图像 y=x^2-3x+2=[x-(3/2)]^2+2-(9/4) 对称轴:x=3/2 原函数:y=x^2+x=[x+(1/2)]^2-(1/4) 对称轴:x=-1/2 a=(3/2)-[-(1/2)]=4/2=2 将函数y=x方+x的图像向右平移a(a>0)个单位,,就是将它的对称轴向右移动a个单位,原来y=x^2+x的对称轴是x=-1/2,现在变成了x=3/2,所以移动单位是a=(3/2)-(-1/2)=2

常乳宽3608x+xy+y=0的图像 -
邰言贷18992508708 ______[答案] y=-x/(x+1) 即是把函数y=1/x的图像向右平移一个单位,再向上平移一个单位可得

常乳宽3608y=︱x+1︱+︱x - 2︱的图像怎么画 -
邰言贷18992508708 ______ 你要去掉绝对值,才能画 当x+1>0,且X-2>0, y=X+1+X-2=2x-1 当x+10,y=-x-1+x-2=-3 此曲线不存在 当X+10,X-2

常乳宽3608x+y+z=0是什么图形 -
邰言贷18992508708 ______[答案] 一个平面. 它的法向量是(1,1,1),用点法式方程表示就是1*(x-0)+1*(y-0)+1*(z-0)=0,所以它是一个通过原点的平面

常乳宽3608y=|x+1|+|2 - x|的图像怎么画 -
邰言贷18992508708 ______ 就是当-1<x<2时, 画y=3.当x>2时,画y=2x-1,当 x<-1时,画 y=-2x+1 我这是对的

常乳宽3608(x+y - 1) - xy=0怎么解.图像是怎样的图象是什么 -
邰言贷18992508708 ______[答案] (x+y-1)-xy=0 -1+x+y-xy=0 -(1-x)+y-xy=0 -(1-x)+y(1-x)=0 (1-x)(y-1)=0 x=1或y=1 图像是相互垂直的两条直线.

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