sin2x与cos2x怎么转换

隗修天4060f(x)=sin2x+cos2x -
浦马瞿18840896980 ______ f(x)=2^0.5*sin(2x+π/4).所以周期为π,相位π/4,振幅2^0.5. 5点的坐标:(0,1)、(π/4,1)、(π/2,-1)、(3π/4,-1)、(π,1)

隗修天4060y=sin2x cos2x周期怎么算,是用到辅助角公式么?那是什么? -
浦马瞿18840896980 ______[答案] y=sin2x cos2x=(sin4x)/2 周期2π x=π/2

隗修天4060函数y=sin2x的图像怎么变换可以得到y=cos2x -
浦马瞿18840896980 ______[答案] y=cos2x=sin(2x+π/2)=sin[2(x+π/4)] 即sin2x的图像向左平移π/4单位得到y=cos2x

隗修天4060有关数学的问题二倍角公式 Sin2x=? Cos2X=? Tan2X=? -
浦马瞿18840896980 ______[答案] sin2x = 2cosxsinx cos2x = 2(cosx)^2 − 1 cos2x = 1 − 2(sinx)^2 cos2x = (cosx)^2 − (sinx)^2 tan2x=2tanx/[1-(tanx)^2]

隗修天40601.如果要把sin2x变为cos2x,在图像上是移动π/2还是π/4 2把sin2x在图像上左移π/2,是sin(2x+π/2)还是sin(2(x - π/2))第二个是把sin2x在图像上左移π/2,是sin(2x+... -
浦马瞿18840896980 ______[答案] sin2x=cos(π/2-2x)=cos[2(x-π/4)] 所以 在图像上是移动π/4 是在x上 2. sin(2x) sin2x在图像上左移π/2 sin[2(x+π/2)]=sin(2x+π)=-sin2x

隗修天4060sin2x+cos2x化简~ -
浦马瞿18840896980 ______ 解:由辅助角公式,sin2x + cos2x = sin(2x + π/4) .

隗修天4060sin2x+cos2x怎么化简 -
浦马瞿18840896980 ______ sin2x+cos2x = 根2·【cos45·sin2x + sin45·cos2x】 = 根2·sin[2x + 45]

隗修天4060sin2x乘 cos2x等于多少? -
浦马瞿18840896980 ______ 你好! sin(2x) * cos(2x) = 1/2 sin(4x)

隗修天4060函数y=sin2x cos2x的周期怎么求? -
浦马瞿18840896980 ______[答案] y=sin2x cos2x =(sin4x)/2 因为,y=(sint)/2的周期与sint的周期一致为T1=2π,而t=4x,所以4T=T1=2π,得出:T=π/2.即,原函数的周期为π/2

隗修天4060sinxsinx转化为sin2x与cos2x -
浦马瞿18840896980 ______[答案] 由cos2x=(cosx)^2-(sinx)^2 得(sinx)^2=(1-cos2x)/2 由sin2x=2sinxcosx 得(sinx)^2={1-√[1-(sin2x)^2]}/2