九年级组

图片内容：载人飞船返回地球过程中，穿过大气层时与大气剧烈摩擦，产生大量的热量；着陆前再打开降落伞来减速，最终安全着陆（模拟图）

图片内容：串联电路的电流处处相等

素材应用：串联电路的电流特点。

图片内容：并联电路的干路电流等于各支路电流之和

素材应用：并联电路的电流特点。

图片内容：并联电路的支路电流与支路电阻成反比

素材应用：欧姆定律、并联电路的特点。

图片内容：电源短路时，电路中电流过大，容易烧坏电源

素材应用：短路。

图片内容：楼梯灯控制演示

素材应用：电流与电路。

图片内容：楼梯灯开关是怎样控制电路的

素材应用：电流与电路、电路设计。

楼梯灯开关控制电路的原理：

上楼时，按下楼下开关，开关由2拨向3，此时楼梯灯电路为通路，灯亮；上楼后，按下楼上开关，开关由6拨向5，此时楼梯灯电路断开，灯熄灭。

下楼时，按下楼上开关，开关由5回到6，楼梯灯电路再次接通，灯亮；下楼后，按下楼下开关，开关由3回到2，楼梯灯电路断开，灯熄灭。

图片内容：病房呼叫演示

素材应用：串联与并联电路。

图片内容：病房呼叫原理电路图

素材应用：串联与并联、电路设计。

八年级组

图片内容：天舟三号货运飞船与空间站完成对接

素材应用：运动和静止的相对性。

▲倒车雷达

▲回声定位

▲B超

▲声呐

图片内容：水中倒影

素材应用：光的反射、平面镜成像

图片内容：影子1

素材应用：光的直线传播

图片内容：影子2

素材应用：光的直线传播

图片内容：影子3

素材应用：光的直线传播

图片内容：眼睛看近物时，晶状体变厚，折光能力变强

素材应用：眼睛与眼镜。

图片内容：眼睛看远物时，晶状体变薄（平），折光能力变弱

素材应用：眼睛与眼镜。

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巫晨闸3813> 直角去判断一个角是锐角还是钝角 - 数学二年级上:《锐角与钝角》教学实录 -
公杨制13032314392 ______ ·锐角直角钝角平角周角 2 教学设计 锐角直角钝角平角周角 2 教学设计 [教学目标] 1、体会引入量角器的必要性,认识量角器. 2、会用量角器测量各种角的度数. [教学重、难点] 1、认识量角器. 2、会用量角器测量各种角的度数. [教学准备]...

巫晨闸3813如何利用学案导学提高教学的实效性 -
公杨制13032314392 ______ 新《课程标准》指出:“人人学有价值的数学;人人都能获得必需的数学;不同的人在数学上得到不同的发展.”课堂教学是实施素质教育的主阵地,如何优化课堂教学,让课堂40分钟焕发无限生机,如何提高数学课堂教学的有效性,让数学课...

巫晨闸3813数学反比例函数3.已知y=y1+y2,y1与(x - 1)成正比例,
公杨制13032314392 ______ 依题意可设y=m(x-1)+n/x 因x=2时,y=1;x=-2时,y=-2. 故: 1=m(2-1)+n/1 (1) -2=m(-2-1)+n/(-2) (2) 解(1)、(2)得 m=3/5 n=2/5. 故函数表达式为: y=3/5*(x-1)+(2/5)/x.

巫晨闸3813反比例的意义 -
公杨制13032314392 ______ 两种相关联的量,一种量随另一种量变化而变化,但这两种量的积一定是个常数,这时,这两种量是成反比例的量,它们的关系叫做反比例关系.

巫晨闸3813一杯水能溶解多少食盐教学设计 -
公杨制13032314392 ______ 《一杯水能溶解多少食盐》教学设计 一、教学目标 1、科学概念:一定量的水只能溶解一定的食盐. 2、过程与方法:设计“一杯水能溶解多少食盐”的实验,经历简单的探究性实验过程. 3、情感、态度、价值观: ①体验研究溶解现象的乐趣...

巫晨闸3813教学设计的一般过程包括什么 -
公杨制13032314392 ______ 一个完整的教学设计应该包括教学内容,教学目标,教学重难点,教学准备,教学过程,板书设计以及课后反思.其中教学过程里面又包括导入环节,新知呈现环节,操练环节,知识拓展与巩固环节,再加上总结环节. 教学设计是根据课程标...

巫晨闸3813反比例的意义是什么? -
公杨制13032314392 ______ 反比例关系是通过应用题的总数与份数关系帮助学生认识的.在总数与份数关系中,包含总数、份数和每份数.当总数一定时,每份数和份数是两种相关联的变量.如果每份数变化,份数也随着变化.同样如果份数变化,每份数也随着变化....

巫晨闸3813y与x成反比例,且比例系数为1,列得函数关系式为?y与1/x成反?
公杨制13032314392 ______ y与x成反比例,且比例系数为1,列得函数关系式为 y=1/x. y与1/x成反比例,且比例系数为1,列得函数关系式为 y=1*x--->y=x.

巫晨闸3813设y=y1y2,y1与x成正比例,y2与x成反比例,并且当x=1?
公杨制13032314392 ______ 设y=y1 y2,y1与x成正比例,y2与x成反比例,并且当x=1时,y1=1,y2=2,求当x=3时函数y=y1 y2的值解:设y1=k1xy2=k2/x当x=1时,y1=k1=1,y2=k2=2所以y1=xy2=1/x当x=3时函数y=y1 y2的值y1=3y2=1/3y=y1 y2=3 (1/3)=10/3