arctanx+arccot

暨秆柴3446证明恒等式arctanx+arccotx=π/2 , f(x) = arctanx+arccotx, 则有f'(x) = 1/(1 + x^2) - 1/(1 + x^2) = 0,f(x) = arctanx+arccotx,则有f'(x) = 1/(1 + x^2) - 1/(1 + x^2) = 0,... -
广眨竖19532099632 ______[答案] 那个f'(x)就相当于导数,倒数为零就意味着f(x)的图像为一条水平线,即f(x)为一常数,所以无论是谁都得TT/2

暨秆柴3446arctanX+arccotX=π/2怎么证明 -
广眨竖19532099632 ______ 左边对x求导 导数为零 说明为常值 再取特殊值如pai/4 得证

暨秆柴3446数学题.证明arctanx+arccotx=1/2 -
广眨竖19532099632 ______ 你这个一开始就是错的哦,是等于π/2 tan(arctanx)=x=tan(π/2-arccotx) arctanx=π/2-arccotx arctanx+arccotx=π/2

暨秆柴3446当X≥1时,arctanx+arccox(2x/1+x2)=π/4 -
广眨竖19532099632 ______ 原式是:arctanx+arccos(2x/1+x2)=π/4?① sinarctanx=x/(√(1+x^2));cosarctanx=1/(√(1+x^2)); cosarccos(2x/1+x2)=2x/(1+x^2);sinarccos(2x/1+x2)=(1-x^2)/(1+x^2); ①式两边求sin得:x/(√(1+x^2))*2x/(1+x^2)+1/(√(1+x^2))*(1-x^2)/(1+x^2)=√2/2; 即2x^2+1-x^2=√(1+x^2)*(1+x^2)*√2/2;√(1+x^2)=√2; X=1

暨秆柴3446arctane^x+arctane^ - x=求详细步骤 -
广眨竖19532099632 ______ 显然e^x *e(-x)=1,而tanx *cotx=1 那么 arctane^x +arctane^(-x)=arctane^x +arccot e^x 而显然arctanx+arccotx=π/2 所以 arctane^x +arctane^(-x)=π/2

暨秆柴3446c语言里arctanx,arccotx,arcsinx,arccosx怎么表示. -
广眨竖19532099632 ______ arctanx=1/tanx arccotx=1/cotx arcsinx=1/sinx arccosx=1/cosx

暨秆柴3446证明:arcsinx+arccosx=π/2,x∈[ - 1,1] -
广眨竖19532099632 ______ 令f(x)=arccosx+ arcsinx,则f(x)'=-1/√(1-x^2)+1/√(1-x^2)=0,说明f(x)是一个恒定不变的常数. 而f(0)=arccos0+ arcsin0=PI/2+0=π/2,所以f(x)=PI/2,即arccosx+ arcsinx=π/2. 其他公式 cos(arcsinx)=√(1-x^2) arcsin(-x)=-arcsinx arccos(-x)=π-...

暨秆柴3446证明:arctanx+arccotx=π/2
广眨竖19532099632 ______ y=arctanx+arccotx y对x的导数=0 y=常量 又当=1时, y= π/2 所以对任意的x, y=arctanx+arccotx=π/2

暨秆柴3446arctanx+arccotx=90怎么证 -
广眨竖19532099632 ______ y=arctanx (1) tany = x cot(π/2- y) = x π/2- y = arccotx (2) (1)+(2) arctanx+arccotx =y+π/2- y = π/2

暨秆柴3446arctanx+arctan(1/x)=?已知x>0. -
广眨竖19532099632 ______[答案] let tana = x then arctanx = a cota = 1/x arctan(1/x) = 90°-a arctanx+arctan(1/x)= 90°