tanx除以tan3xx趋于90度

童沈睿2484求极限limx→0[ tanx - tan(sinx)]sinx/x^3arctanxlimx→0[ tanx - tan(sinx)]sinx/x^3arctanx -
龙陆咏19861073249 ______[答案] 原式=limx→0 [tanx-tan(sinx)]/x^3*limx→0 sinx/x*limx→0 x/arctanx =limx→0 [1/cos^2x-cosx/cos^2(sinx)]/3x^2*1*1 =limx→0 [cos^2(sinx)-cos^3x]/3x^2*limx→0 1/[cos^2x*cos^2(sinx)] =limx→0 [-2cos(sinx)sin(sinx)cosx+3cos^2xsinx]/6x*1 =limx→0 [3sin2x-2...

童沈睿2484tanxtan2x+ta2xtan3x+...+tannxtan(n - 1)x= -
龙陆咏19861073249 ______[答案] tanx=[tan(k+1)x-tankx]/[1+tan(k+1)xtankx]tan(k+1)xtankx=[tan(k+1)x-tankx]/tanx -1所以原式=[(tan2x-tanx)/tanx-1]+[(tan3x-tan2x)/tanx-1]+...+[(tannx-tan(n-1)x)/tanx-1]=[tannx-tanx]/tanx-(n-1)=tannx/tanx...

童沈睿2484已知tanx=3,则tan2(x - π/4)等于 -
龙陆咏19861073249 ______[答案] Tan2(x-∏/4)={2tan(x-∏/4)}/{1-tan2(x-∏/4)}下求tan(x-∏/4)的值.tan(x-∏/4)={tanx-tan∏/4}/{1+ tanx * tan∏/4}=(3-1)/(1+3*1)=1/2所以Tan2(x-∏/4)=(2*1/2)/(1-(1/2)2)=4/3

童沈睿2484求证tanxtan2x+tan2xtan3x+tan3xtan4x+.+tan(m - 1)xtanmx=tanmx/tanx - m -
龙陆咏19861073249 ______[答案] tanx=[tanmx-tan(m-1)x]/{1+} 根据差角的正切公式1+tan(m-1)xtanmx=[tanmx-tan(m-1)x]/tanxtan(m-1)xtanmx=-1+[tanmx-tan(m-1)x]/tanx把每一项都表示成为两项之差,刚好相邻的正负可以抵消tanxtan2x+tan2xtan3x+tan3x...

童沈睿2484求证:tan3x - tan2x - tanx=tan3xtan2xtanx -
龙陆咏19861073249 ______[答案] 由于在这里输入太烦,我在Word的公式编辑器做的,但不好复制,所以就给你截图了,应该可以看得清楚

童沈睿2484化简tanxtan2x/tan2x - tanx,所得结果是 -
龙陆咏19861073249 ______[答案] tanxtan2x/tan2x-tanx=2tan^2x/1-tan^2x/2tanx-tanx(1-tan^2x)/1-tan^2=2tan^2x/2tanx-tanx(1-tan^2x)=2tan^2x/tanx+tan^3x=2tanx/1+tan^2x=(2sinx/cosx)/(1/cos^2x)=2sinx/cosx*cos^2x=2sinxcosx=sin2x

童沈睿2484化简tanxtan2x+tan2xtan3x+.+tan2009xtan2010x速度啊.谢谢. -
龙陆咏19861073249 ______[答案] 1+tan2009xtan2010x=(tan2010x-tan2009x)/tanx.1+tan2xtan3x=(tan3x-tan2x)/tanx1+tanxtan2x=(tan2x-tanx)/tanx等号两边相加得:2009+tanxtanx+tan2xtan3x+...+tan2009xtan2010x=(1/tanx)(tan2x-tanx+tan3x-tan2x+.....

童沈睿2484tanx^3的不定积分 是 问(tanx)^3 不是问 tan(x^3).. -
龙陆咏19861073249 ______[答案] =∫tanx(tan²x)dx =∫tanx(sec²x-1)dx =∫tanxsec²xdx-∫tanxdx =∫tanxdtanx-∫(sinx/cosx)dx =(tan²x)/2-∫-dcosx/cosx =(tan²x)/2+ln|cosx|+C

童沈睿2484tanx=3 tan 2分之x是多少 -
龙陆咏19861073249 ______[答案] tanx=tan(2*x/2)=(tan x/2+tan x/2)/(1-tan x/2*tan x/2)=6/(1-9)=-3/4

童沈睿2484tan3x还可以化简成什么 -
龙陆咏19861073249 ______