sin2x+cos2x化简结果

邵龙肯1716sin2x+ cos2x怎么化解 -
贝轻卫13456821235 ______ sin2x+ cos2x=√2sin(2x+π/4)

邵龙肯1716fx=2sin2x+2cosx,化简? -
贝轻卫13456821235 ______[答案] =2(sin2x+cos2x) ==2√2(√2/2sin2x+√2/2cos2x) =2√2sin(2x+π/4)

邵龙肯1716f(x)=sin2x+cos2x化简 要详细过程 -
贝轻卫13456821235 ______ 解:直接利用辅助角公式 得√2sin(2x+π/4) 很高兴为您解答,祝你学习进步!不懂可追问!

邵龙肯1716sin2x+cos2x+2如何化简sin2x+cos2x如何化为根号2sin(2x+π/4)? -
贝轻卫13456821235 ______[答案] sin2x+cos2x+2=根号2倍的sin(2x+π/4)+2 sin2x+cos2x=根号2倍的sin(2x+π/4)

邵龙肯1716 - 2sin2x+cos2x的化简结果是什么? -
贝轻卫13456821235 ______[答案] -2sin2x+cos2x=cos2x-2sin2x =√5[1/√5cos2x-2/√5sin2x] =√5cos(2x+α) 其中cosα=1/√5 不过这一般不用化解!

邵龙肯1716y=sin2x+cos2x化简成y=Asin(wx+t)形式,并求最小正周期 -
贝轻卫13456821235 ______ 原式=根号2(根号2/2 sin2x+根号2/2 cos2x) =根号2sin(π/4+2x) 所以T=2π/w=2π/2=π

邵龙肯1716化简函数f(x)=根号三倍的sin2x+cos2x -
贝轻卫13456821235 ______[答案] =√3sin2x+cos2x =2(sin2x* √3/2+cos2x* 1/2) =2(sin2xcos30°+cos2xsin30°) =2sin(2x+30°)

邵龙肯1716sin2x的平方+cos2x 化简 -
贝轻卫13456821235 ______ sin²x+cos2x =sin²x+(cos²x-sin²x) =cos²x

邵龙肯1716为什么sin2x+cos2x=2sin(2x+π/4) -
贝轻卫13456821235 ______[答案] sin2x+cos2x=(根号下2)sin(2x+π/4) sin2x+cos2x=(根号下2)[根号下2/2sian2x+根号下2/2cos2x] =(根号下2)[cosπ/4sin2x+sinπ/4cos2x] =(根号下2)sin(2x+π/4)

邵龙肯1716sin2x+cos2x=根号2sin(2x+四分之派)怎么求的 -
贝轻卫13456821235 ______[答案] sin2x+cos2x =√2(√2/2·sin2x+√2/2·cos2x) =√2(sin2xcosπ/4+cos2xsinπ/4) =√2sin(2x+π/4)