e+x+y
日前智电出行获悉，特斯拉新款Model X车型将换装全新Matrix LED头灯组，并可在开启远光灯行驶的状态下，实现单一一侧车灯迎面变暗等功能。同时，品牌旗下新款Model 3、Model Y以及Model S车型也将适配Matrix LED头灯组，其中前者也已确认将于今年7月全球首发，并将于今年三季度在上海工厂以及海外工厂开启投产工作，同级主要竞争对手涵盖了比亚迪海豹、蔚来ET5以及小鹏P7等车型。
另据此前特斯拉内部员工透露，代号为“Project Highland”的新款Model 3车型，计划将于2024年一季度上市开售，外观方面换装了全新的Matrix LED头灯组，并在头部加入了全新摄像头。同时，新车内部也已确认将首次配备液晶仪表，并搭载更新后的可倾斜式液晶中控屏幕，且取消怀挡式换挡机构。
同时，内部代号Project Juniper的新款Model Y车型也将于2024年三季度正式推出，预计最快将于同年四季度上市开售。据悉，新车也有望首次配备新款Model 3相同的液晶数字仪表，并对车身尺寸方面进行小幅调整，且采用2+3+2七座布局设计。
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戈聂玉1857求微分方程y'=e^(x+y)满足初始条件y(0)=0的特解 -
国残董17376723777 ______ y'=(e^x)(e^y)e^(-y)dy=e^xdx-e^(-y)=e^x+C代入得C=-2特解为e^x+e^(-y)=2或y=-ln(2-e^x)
戈聂玉1857e^(x+y)+xy=0求一阶导数和二阶导数 -
国残董17376723777 ______ e^(x+y)+xy=0两边对x求导得: e^(x+y)*(1+y')+y+xy'=0,解得:y'=-(e^(x+y)+y)/((e^(x+y)+x))=(xy-y)/(x-xy) e^(x+y)*(1+y')+y+xy'=0两边对x求导得: e^(x+y)*(1+y')^2+y''e^(x+y)+2y'+xy''=0 解得:y''=-(e^(x+y)*(1+y')^2+2y')/((e^(x+y)+x)) =(xy(1+y')^2-2y')/(x-xy) 代入y'=(xy-y)/(x-xy)即可
戈聂玉1857急急急!!!已知xy=e的x+y次幂,求y的导数~~~~~谢谢 -
国残董17376723777 ______ xy=e^(x+y) 两边对x求导得:y+xy'=(1+y')e^(x+y) y'=[y-e^(x+y)]/[e^(x+y)-x]
戈聂玉1857求由方程xy=e^(x+y)确定的隐函数y的导函数y' -
国残董17376723777 ______ xy=e^(x+y) 两边对x求导得 y+xy'=e^(x+y)(1+y') y-e^(x+y)=[e^(x+y)-x]y' y'=[y-e^(x+y)]/[e^(x+y)-x]
戈聂玉1857如果e^(x+y)+xyz=e^z,则dz=? -
国残董17376723777 ______ 两边同时求微分得:e^(x+y) ·(dx+知dy)+yzdx+xzdy+xydz=道e^z· dz 移项得:(e^z-xy)dz=e^(x+y) ·(dx+回dy)+yzdx+xzdy =e^(x+y)dx+e^(x+y)dy+yzdx+xzdy =[e^(x+y) +yz]dx + [e^(x+y) +xz]dy ∴dz=﹛[e^(x+y) +yz]dx+[e^(x+y) +xz]dy﹜/(e^z-xy) =[e^(x+y) +yz]dx/(e^z-xy) + [e^(x+y) +xz]dy/(e^z-xy) 其实答楼上的就对,只是没化简到最后而已
戈聂玉1857xy=e^(x+y)求导 -
国残董17376723777 ______ 肯定是你算错了吧 xy=e^xe^y 两边同时对x求导得 y+xy'=e^x*e^y+e^x*e^y*y'(x-e^x*e^y)y'=e^x*e^y-y 所以 y'=(e^x*e^y-y)/(x-e^x*e^y) 和老师的答案一样啊.
戈聂玉1857设y=f(x)是由方程e^x+y+xy^2=1确定,求y'(0)的值 -
国残董17376723777 ______ 设y=f(x)是由方程e^x+y+xy^2=1确定,\ x=0代入,得1+y=1 y=0 两边同时对x求导,得 e^x+y'+y²+2xyy'=0 x=0,y=0同时代入,得1+y'(0)+0+0=0 y'(0)=-1
戈聂玉1857x=e的x次方+y次方 怎么求隐含数 -
国残董17376723777 ______ 郭敦顒回答: 将隐函数x=ex+y化为显函数, 对x=ex+y两边取对数得, lnx=lnex+y, ∴lnx=(x+y)lne, x+y=lnx, ∴y=lnx-x.
戈聂玉1857设X,Y都是n维列向量,且X^T*Y=1,矩阵A=E+X*Y^T,说明A是可逆矩阵,并求A^ - 1 -
国残董17376723777 ______[答案] A^2=E+2X*Y^T+X*Y^TX*Y^T=E+3X*Y^T=3A-2E A^2-3A=-2E A(A-3E)=-2E A^-1=0.5(3E-A)
戈聂玉1857e^(x+y)sin(x+z)=0 z=z(x+y) 求dz -
国残董17376723777 ______ e^(x+y)sin(x+z)=0e^(x+y)dsin(x+z)+ sin(x+z)de^(x+y)=0e^(x+y).cos(x+z) ( dx +dz) + sin(x+z).e^(x+y).( dx+ dy) =0e^(x+y).cos(x+z) dz =-sin(x+z).e^(x+y).( dx+ dy) -e^(x+y).